A jet starts from rest and accelerates to a speed of 100 m/s in 10 seconds before taking off. how far does it travel before taki
2 answers:
Answer:
Explanation:
We want to find the distance the jet travels. Distance can be found by multiplying the speed by the time.
The speed is 100 meters per second.
The time is 10 seconds.
Substitute the values into the formula.
Multiply. Note that the seconds, or "s" will cancel each other out.
The jet travels <u>1,000 meters</u> before taking off.
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The magnitude of the electric field for 60 cm is 6.49 × 10^5 N/C
R(radius of the solid sphere)=(60cm)( 1m /100cm)=0.6m
Since the Gaussian sphere of radius r>R encloses all the charge of the sphere similar to the situation in part (c), we can use Equation (6) to find the magnitude of the electric field:
Substitute numerical values:
The spherical Gaussian surface is chosen so that it is concentric with the charge distribution.
As an example, consider a charged spherical shell S of negligible thickness, with a uniformly distributed charge Q and radius R. We can use Gauss's law to find the magnitude of the resultant electric field E at a distance r from the center of the charged shell. It is immediately apparent that for a spherical Gaussian surface of radius r < R the enclosed charge is zero: hence the net flux is zero and the magnitude of the electric field on the Gaussian surface is also 0 (by letting QA = 0 in Gauss's law, where QA is the charge enclosed by the Gaussian surface).
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