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4 years ago

Can someone help me with science

Physics

1 answer:

tamaranim1 [39]4 years ago

6 0

The continuious physical force per unit area that one region of a gas, liquid, or solid exerts on another.

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Parallel conducting tracks, separated by 2.20 cm, run north and south. There is a uniform magnetic field of 1.20 T pointing upwa

mars1129 [50]

Answer:

The magnitude of the magnetic force on the rod is 0.037 N.

Explanation:

The magnetic force is given by:

$F = qvBsin(\theta)$

Since the charge (q) is:

$q = I*t$

Where I is the current = 1.40 A, and t the time

And the speed (v):

$v = \frac{L}{t}$

Where L is the tracks separation = 2.20 cm = 0.022 m

Hence, the magnetic force is:

$F = ILBsin(\theta)$

Where B is the magnetic field = 1.20 T and θ is the angle between the tracks and the magnetic field = 90°

$F = ILBsin(\theta) = 1.40*0.022*1.20*sin(90) = 0.037 N$

Therefore, the magnitude of the magnetic force on the rod is 0.037 N.

I hope it helps you!

5 0

3 years ago

The first published controlled experiment was designed to

Viktor [21]

Your answer for the question is B.) prove that bacteria arise spontaneously from broth

4 0

3 years ago

Read 2 more answers

The Hubble Space Telescope orbits the Earth at approximately 612,000m altitude. Its mass is 11,100 kg and the mass of earth is 5

nexus9112 [7]

Answer:

7.55 km/s

Explanation:

The force of gravity between the Earth and the Hubble Telescope corresponds to the centripetal force that keeps the telescope in uniform circular motion around the Earth:

$G\frac{mM}{R^2}=m\frac{v^2}{R}$

where

$G=6.67\cdot 10^{-11} m^3 kg^{-1} s^{-2}$ is the gravitational constant

$m=11,100 kg$ is the mass of the telescope

$M=5.97\cdot 10^{24} kg$ is the mass of the Earth

$R=r+h=6.38\cdot 10^6 m+612,000 m=6.99\cdot 10^6 m$ is the distance between the telescope and the Earth's centre (given by the sum of the Earth's radius, r, and the telescope altitude, h)