Answer:
15.19°, 31.61°, 51.84°
Explanation:
We need to fin the angle for m=1,2,3
We know that the expression for wavelenght is,

Substituting,


Once we have the wavelenght we can find the angle by the equation of the single slit difraction,

Where,
W is the width
m is the integer
the wavelenght
Re-arrange the expression,

For m=1,

For m=2,

For m=3,

<em>The angle of diffraction is directly proportional to the size of the wavelength.</em>
I mean if he flies 5g that means that's his average speed too
that is an example of negative acceleration because it is slowing down