All categories

3 years ago

Which of the following expressions has a coefficient of 10 and a constant of 5

Mathematics

1 answer:

adell [148]3 years ago

8 0

Answer:

sometinng like x^2+ 10x+5

The single number is the constant and the number before the variable(x) is the coefficient

Step-by-step explanation:

You might be interested in

12. If n(A) = 14, n(B) = 15, and n(<br>AB) = 6, then n(AUB) is<br>

motikmotik

Answer:

given n(A) = 14

n(B) = 15

n(A∩B ) = 15

Step-by-step explanation:

now we know that ,n(AUB) = n(A)+n(B)-n(A∩B)

n(AUB) = 14+15-6 = 23.Answer

3 0

3 years ago

Read 2 more answers

Marge cut 16 pieces of tape for mounting pictures on posterboard each piece of tape is 3/8 inches long how much tape did Marge u

daser333 [38]

Answer:

6 inches of tape

Step-by-step explanation:

To find the total amount of tape that Marge used, you can take the measure of each piece ( $\frac{3}{8}$ ) and multiply by the total number of pieces cut (16):

$\frac{3}{8}*\frac{16}{1}=\frac{48}{8}=6inches$

So, Marge used 6 inches of tape altogether.

7 0

3 years ago

100 POINTSbrainlest to the person who get it right

Zina [86]

Answer:

[1] x² - 4/2x - 4

3² - 4/2 × 3 - 4 = 9 - 4/2
5/2

[2] 4 - 3x/2x + 4

4 - 3 × 2/2 × 2 + 4 = 2/8
1/4

[3] x²/2x² - 2

0²/2 × 0² - 2
0

[4] x² + 5/5 - x

- 2² + 5/5 + 2 = 4 + 5/7
9/7

[5] - x³/x² - 4

- 1³/-1² - 4 = - 1/1 - 4
1/3

[6] x + 3/x³ - 1

- 3 + 3/- 3³ - 1 = 0/- 27 - 1
0

[7] 5 - x²/3x²

5 - (- 4)²/3 × - 4² = 5 - 16/3 × 16
- 11/48

[8] - 2x + 6/2x³ - 3

- 2 × - 2 + 6/2 × - 2³ - 3
10/- 19

[9] 4x²/- 3x² + 1

4 × 1²/- 3 × 1² + 1 = 4/- 2
- 2

[10] 4x - 1/6x + 1

4 × 3 - 1/6 × 3 + 1
11/19

[11] x² - 1/x² + 1

1² - 1/1² + 1 = 0/2
0

8 0

3 years ago

Read 2 more answers

What would x be equal to?

Vilka [71]

Answer:

x = $\frac{C-By}{A}$

Step-by-step explanation:

Given

Ax + By = C ( subtract By from both sides )

Ax = C - By ( divide both sides by A )

x = $\frac{C-By}{A}$

4 0

3 years ago

OOOO

lbvjy [14]

Step-by-step explanation:

Given bi-quadratic equation is:

$x^4+95x^2 -500=0$

Substituting $x^2=a,$ given bi-quadratic equation reduces in the form of following quadratic equation:

$a^2 +95a -500=0\\$

Let us factorize the above quadratic equation:

$a^2 +95a -500=0\\\therefore\: a^2 +100a -5a-500=0\\\therefore\: a(a +100) -5(a+100)=0\\\therefore\: (a +100)(a -5)=0\\\therefore\: (a +100)=0\:\: or \:\: (a -5)=0\\\therefore\: a = - 100\:\: or \:\: a = 5\\\\CASE\: (1)\:\\When\: a = - 100 \implies x^2 = - 100\\\therefore x=\pm \sqrt{-100}\\$

Since square root of a negative number cannot be found, so:

$x \neq \pm \sqrt{-100}\\$

$CASE\: (2)\:\\When\: a =5 \implies x^2 =5\\\therefore x=\pm \sqrt{5}\\$

3 0

3 years ago