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IgorC [24]
3 years ago
10

A sealed flask contains Ne, Ar, and Kr gas. If the total pressure in the flask is 3.782 atm, the partial pressure of Ne is 0.435

atm, and the partial pressure of Kr is 1.613 atm, what is the partial pressure of Ar
Chemistry
1 answer:
spin [16.1K]3 years ago
4 0

Answer:

P_{Ar}=1.734atm = partial pressure of Ar

Explanation:

Acccoding to dalton's law of partial pressure total pressure of system is equal to alzebraic sum of all partial pressure.

P_{total} =P_{Ne}+P_{Ar} +P_{Kr}

P_{total}=3.782atm

P_{Ne}=0.435 atm

P_{Kr}=1.613atm

P_{Ar}=P_{total}-P_{Ne}-P_{Kr}

P_{Ar}=3.782-0.435-1.613

P_{Ar}=1.734atm =partial pressure of Ar

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Answer:

Acetic acid 0,055M and acetate 0,095M.

Explanation:

It is possible to prepare a 0,15M buffer of acetic acid/acetate at pH 5,0 using Henderson-Hasselblach formula, thus:

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Replacing:

5,0 = 4,76 + log₁₀ [A⁻]/[HA]

<em>1,7378 =  [A⁻]/[HA] </em><em>(1)</em>

As concentration of buffer is 0,15M, it is possible to write:

<em>[A⁻] + [HA] = 0,15M </em><em>(2)</em>

Replacing (1) in (2):

1,7378[HA] + [HA] = 0,15M

2,7378[HA] = 0,15M

[HA] = 0,055M

Thus, [A⁻] = 0,095M

That means you need <em>acetic acid 0,055M</em> and <em>acetate 0,095M</em> to obtain the buffer you need.

i hope it helps!

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