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dexar [7]
3 years ago
5

Please help me ASAP I’ll mark Brainly

Chemistry
2 answers:
shutvik [7]3 years ago
8 0

Answer:

Pros: Oil can easily be transported by a network of pipelines.

Oil-fired power stations can, in theory, be built almost anywhere.

The oil is burned to heat water and produce steam. This steam propels the blades of a turbine. This is attached to a generator, which produces electricity.

Cons: Oil is a non-renewable source of energy. This means that one day we will probably run out of crude oil.

Burning oil produces carbon dioxide gas. This is a greenhouse gas that contributes towards climate change.

Burning oil can pollute the air.

Much of our oil has to be imported and it is becoming more and more expensive as reserves reduce and imports increase.

Producing electricity from crude oil is expensive compared to other fossil fuels such as coal or gas.

Explanation:

expeople1 [14]3 years ago
3 0

Answer:

- Oil Energy is a Major Source of Pollution and Damage Made to the Environment Every Year.

- Oil Like the Other Fossil Fuels Is A Finite Resource.

- Emissions Produced by Oil Causes Acid Rain

-Plastic is One of the Products Obtained Through Oil Refining.

- Working in the Oil Sector Can Be a Dangerous Activity.

hope this is good enough :)

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How many grams of cupric sulfate pentahydrate are needed to prepare 50.00 mL of 0.0800M CuSO4× 5H2O?
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Explanation:

Molarity is defined as number of moles per liter of solution.

Mathematically,         molarity = \frac{no. of moles}{Volume (in L) of solution}

It is given that molarity is 0.0800 M and volume is 50.00 mL or 0.05 L.

           molarity = \frac{no. of moles}{Volume of solution in liter}

            0.0800 M = \frac{no. of moles}{0.05 L}

            no. of moles = 1.6 mol

Therefore, molar mass of cupric sulfate pentahydrate is 249.68 g/mol. So, calculate the mass as follows.

                No. of moles = \frac{mass in grams}{molar mass}

             mass in grams = no. of moles \times molar mass of CuSO_{4}.5H_{2}O

                                       = 1.6 mol \times 249.68 g/mol

                                       = 399.488 g

Thus, we can conclude that 399.488 g of cupric sulfate pentahydrate are needed to prepare 50.00 mL of 0.0800M CuSO4× 5H2O.

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