What is the percent composition for HCl
1 answer:
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Answer:
a) 231.9 °C
b) 100% Sn
c) 327.5 °C
d) 100% Pb
Explanation:
This is a mixture of two solids with different fusion point:
<u>Given that Sn has a lower fusion temperature it will start to melt first at that temperature. </u>
So the first liquid phase forms at 231.9 °C and because Pb starts melting at a higher temperature, that phase's composition will be 100% Sn.
The mixture will be completely melted when you are a the higher melting temperature of all components (in this case Pb), so it will all in liquid phase at 327.5 °C.
At that temperature all Sn was already in liquid state and, therefore, the last solid's composition will be 100% Pb.
The atomic number of Fe= 26
The electronic configuration of Fe will be
1s2 2s2 2p6 3s2 3p6 4s2 3d6
When it loses two electrons to form ferrous ion (Fe(II)) the electrons will be loose by 4s orbital first
So the electronic configuration of Fe^+2 ion will be
1s2 2s2 2p6 3s2 3p6 3d6
Hence there are six electrons in 3d orbital of iron dipositive ion
Now the the electrons in 3d orbital will be like:
so there are four unpaired electrons
