<h3>
Answer:</h3>
78 L Cl₂
<h3>
General Formulas and Concepts:</h3>
<u>Math</u>
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Chemistry</u>
<u>Atomic Structure</u>
- Reading a Periodic Table
- STP (Standard Conditions for Temperature and Pressure) = 22.4 L per mole at 1 atm, 273 K
<u>Stoichiometry</u>
- Using Dimensional Analysis
<h3>
Explanation:</h3>
<u>Step 1: Define</u>
280 g Cl₂
<u>Step 2: Identify Conversions</u>
[PT] Molar Mass of Cl - 35.45 g/mol
Molar Mass of Cl₂ - 2(35.45) = 70.90 g/mol
[STP] 1 mol = 22.4 L
<u>Step 3: Convert</u>
- [DA] Set up:
- [DA] Multiply/Divide [Cancel out units]:
<u>Step 4: Check</u>
<em>Follow sig fig rules and round. We are given 2 sig figs.</em>
78.4981 L Cl₂ ≈ 78 L Cl₂
Answer:
A - right shift
B - no shift
C - right shift
Explanation:
<em>According to Le Chatelier's principle, when a reaction is in equilibrium and one of the factors affecting the rate of reaction is introduced, the equilibrium will shift so as to annul the effects of the constraint. </em>
In this case, decreasing the volume of the reaction's container is equivalent to increasing the pressure of the reaction. When pressure is increased, the reaction will shift towards the side with a lower number of moles.
In A, the total number of moles on the left-hand side of the reaction is two while it is one on the right-hand side. <em>An increase in pressure will, therefore, see the equilibrium shifting to the right-hand side.</em>
In B, the total number of moles on both the right and the left-hand side is two each. <em>An increase in the pressure will have no effect on the equilibrium.</em>
In C, the total number of moles on the left-hand side is two while it is one on the right-hand side. <em>Hence, an increase in the pressure of the reaction will cause a shift in the equilibrium to the right. </em>
Answer:
Explanation:
When copper metal is dipped into an aqueous solution of 
, copper nitrate (
) is formed. This is type of displacement reaction because copper metal displaces silver from its salt. As only one ion is being displaced, therefore, it is a single displacement reaction.
Copper displaces silver as it is more reactive than silver. This can be confirmed by position of copper and silver in reactivity series. Elements above in the reactive series displaces elements present below from their salts.
The molecular equation is as follows:
Now, write the ionic equation as follows:
Cancel the common terms,
27.8 mg of silver nitrate (AgNO3, 169.9g/mol) was dissolved in water to make 15.00 mL of solution. 8.15 mL of that solution was diluted to make a new solution with a total volume of 1.000L.
Answer:
Yeasts reproduce asexually by a process called budding (see Figure 8.2. 1 and Figure 8.2. 6). A bud is formed on the outer surface of the parent cell as the nucleus divides.
Explanation:
