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Andrew [12]
3 years ago
14

Pls help and if you can show me how you do it :)

Mathematics
1 answer:
Charra [1.4K]3 years ago
7 0
So basically you want to start by thinking of multiples of 5 less than 40 such as 35, 30, etc. then divide each by six to see if it has a remainder of two. The answer would be 20. 6 goes into 20 3 times. 6x3 = 18. 20-18=2
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A line that passes through [-7,3] and [-6,-1]
juin [17]
Sorry idk, but I’ll try to do it
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3 years ago
Question 13 of 20 :
grin007 [14]

Answer:

C. 70.4

Step-by-step explanation:

22% × 320 =

(22 ÷ 100) × 320 =

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8 0
3 years ago
5v + 7f =28.70 if f is 2.85
adell [148]
Hey!

First, let's write the problem.
5v+7\left(2.85\right)=28.7
Multiply 7 with 2.85.
5v+19.95=28.7
Subtract 19.95 from both sides.
5v+19.95-19.95=28.7-19.95
5v=8.75
Divide both sides by 5.
\frac{5v}{5}=\frac{8.75}{5}
v=1.75

Let me know if you have any questions regarding this problem!
Thanks!
-TetraFish
3 0
3 years ago
Read 2 more answers
The sum of 3 consecutive multiples of 4 is 180.
Paul [167]

9514 1404 393

Answer:

  56, 60, 64

Step-by-step explanation:

The middle of the three numbers is their average: 180/3 = 60. The other two will be 4 more or less than this.

The numbers of interest are 56, 60, 64.

_____

<em>Additional comment</em>

For "consecutive integer" problems, it is often useful to work with the average of the numbers. The average will be the middle number of an odd number of numbers (as here), or will be halfway between the two middle numbers if their number is even.

Even if you bother to write equations, it can work to do that in terms of the average value (middle number): (x -4) +(x) +(x +4) = 180 in this case.

7 0
2 years ago
Solve for g 3g-10=-45​
Goryan [66]

Answer:

g = -18.3

Step-by-step explanation:

3g-10=-45

+10 (Cancel out the 10)

3g=-55

/3 (Divide by 3 to cancel out the 3)

g= -18.3

5 0
3 years ago
Read 2 more answers
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