If in the triangle ABC , BF is an angle bisector and ∠ABF=41° then angle m∠BCE=8°.
Given that m∠ABF=41° and BF is an angle bisector.
We are required to find the angle m∠BCE if BF is an angle bisector.
Angle bisector basically divides an angle into two parts.
If BF is an angle bisector then ∠ABF=∠FBC by assuming that the angle is divided into two parts.
In this way ∠ABC=2*∠ABF
∠ABC=2*41
=82°
In ΔECB we got that ∠CEB=90° and ∠ABC=82° and we have to find ∠BCE.
∠BCE+∠CEB+EBC=180 (Sum of all the angles in a triangle is 180°)
∠BCE+90+82=180
∠BCE=180-172
∠BCE=8°
Hence if BF is an angle bisector then angle m∠BCE=8°.
Learn more about angles at brainly.com/question/25716982
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Answer:
15/24
Step-by-step explanation:
hope this helps u.
Add 3x and 2x together to get 5x. Then do 88+108-6 and you get 190. To find x now all you have to do is use 5x+190=360 to get x.
360 -190= 170 now you have 5x=170 divide 170/5 and that will give u the value of x.
Try 122.
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Step-by-step explanation:
Since <em>x</em> = 1, x^6 = 1.
Since <em>y</em> = 11, 11^2 = 121.
1 + 121 = 122.
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So, the value of <em>
x</em>
^ 6 + <em>
y </em>
^ 2 = 122.</h3><h3 />
Answer:
0.06
Step-by-step explanation:
