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3 years ago

5

When reacting 45g of magnesium with oxygen, 50.0g of magnesium oxide is produced. Calculate the theoretical yield and percent yi

eld.

1 answer:

Veseljchak [2.6K]3 years ago

5 0

Hope you are able to get it :)

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5. A football field is about 100 meters long. If it takes a person 20 seconds to run its length, how fast (what speed) were they

EleoNora [17]

Answer:

Speed, v = 5 m/s

Explanation:

The length of the football field, l = 100 m

the person takes 20 seconds to run its length

v=

t

d

v=

20 s

100 m

v=5 m/s

7 0

3 years ago

If you burn 59.1 g of hydrogen and produce 528 g of water , how much oxygen is reacted

shtirl [24]

Hydrogen + oxygen --> water
59,1g + x = 528g
528g - 59,1 = x
x = 468,9g

8 0

3 years ago

Is a process that could be used to seperate dissolved particles from the liquid in a solutoin?

kaheart [24]

Salutations!

_____ Is a process that could be used to separate dissolved particles from the liquid in a solution?

Distillation is the process that could be used to separate dissolved particles from the liquid in a solution. Distillation best works when liquids have unalike boiling points. It is widely used to to isolate ethanol.

Hope I helped :D

5 0

3 years ago

Concerning Boyle's Law, if you had a gas at a pressure of 101 kPa and decreased the volume of the container holding the gas to o

Viefleur [7K]

Answer:

$P_2=404 kPa$

Explanation:

Hello,

In this case, the Boyle's is mathematically defined via:

$P_1V_1=P_2V_2$

Which stands for an inversely proportional relationship between volume and pressure, it means the higher the volume the lower the pressure and vice versa. In such a way, since the volume is decreased to one quarter, we can write:

$V_2=\frac{1}{4} V_1$

We can compute the new pressure:

$P_2=\frac{P_1V_1}{V_2} =\frac{P_1V_1}{\frac{1}{4} V_1} =\frac{101kPa*V_1}{\frac{1}{4} V_1} \\\\P_2=4*101kPa\\\\\\P_2=404 kPa$

Which means the pressure is increased by a factor of four.

Regards.

7 0

3 years ago

V2 = (P1 × V1 × T2) (P2 × T1) A gas with a beginning pressure of 2 atm at a temperature of 300 K has a volume of 20 ml. What wil

rusak2 [61]

6.6ml will be the new volume if the pressure increases to 4 atm and the temperature are lowered to 200 K.

<h3>What is an ideal gas equation?</h3>

The ideal gas law (PV = nRT) relates the macroscopic properties of ideal gases. An ideal gas is a gas in which the particles (a) do not attract or repel one another and (b) take up no space (have no volume).

Given data:

$V_1=20 ml$

$T_1=3$

$P_1=2 atm$

$T_2=200 K$

$P_2=4 atm$

$V_2=?$

Using equation:

$V_2 =$ $\frac{P_1 X V_1 XT_2}{P_2 X T_1}$

$V_2 =$ $\frac{2 atm X 20 ml X200 K}{4 atm X 300 K}$

$V_2 = 6.6 ml$

Hence, 6.6ml will be the new volume if the pressure increases to 4 atm and the temperature are lowered to 200 K.

Learn more about the ideal gas equation here:

#SPJ1

6 0

2 years ago