According to my calculations, B (equal to 1) seems to be the correct answer.
Answer:
(a): The ball is in the air t= 0.49 sec.
(b): The speed of the ball in the instant it leaves the table is V= 2.44 m/s.
Explanation:
h= 1.2m
d= 1.52m
h= g*t²/2
t=√(2*h/g)
t=0.49 sec (a)
d= V*t
V= d/t
V= 2.44 m/s (b)
Momentum p = mv is conserved.
before: p = 2.5 * 7.5 + 70 * 0
after: p = (2.5 + 70) * v
p before = p after
2.5 * 7.5 = (2.5 + 70) * v
v = 2.5 * 7.0 / (2.5 + 70)
Vf=vi+at
-23m/s=23m/s-9.8m/s^2(t)
t1 from throwing up back to starting position t1=4.693s
Delta(x)=vi(t)+.5a(t^2)
25-11=14
-14m=-23m/s(t)-4.8m/s^s(t^2)
t2 is from 25m to 11 m t2=.546s
Total time =5.239s
Answer:
Newtons first law
Explanation:
Objects stay at rest until a force acts on it causing it to move from its resting position