Question

A 52 gram sample of an unknown metal requires 714 Joules of energy to heat it from

Answer 1

Answer:  Approximately $0.267 \frac{\text{J}}{\text{g}^{\circ}\text{C}}$

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Work Shown:

We have the following variables

• Q = 714 joules = heat required
• m = 52 grams = mass
• c = specific heat = unknown
• $\Delta t$ = 82-30.5 = 51.5 = change in temperature

note: the symbol $\Delta$ is the uppercase Greek letter delta. It represents the difference or change in a value.

Apply those values into the formula below. Solve for c.

$Q = m*c*\Delta t\\\\714 = 52*c*51.5\\\\714 = 52*51.5*c\\\\714 = 2678*c\\\\2678*c = 714\\\\c = \frac{714}{2678}\\\\c \approx 0.26661687826737\\\\c \approx 0.267$

The specific heat of the unknown metal is roughly $0.267 \frac{\text{J}}{\text{g}^{\circ}\text{C}}$