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exis [7]
3 years ago
11

A 52 gram sample of an unknown metal requires 714 Joules of energy to heat it from

Chemistry
1 answer:
ratelena [41]3 years ago
3 0

Answer:  Approximately 0.267 \frac{\text{J}}{\text{g}^{\circ}\text{C}}

===================================================

Work Shown:

We have the following variables

  • Q = 714 joules = heat required
  • m = 52 grams = mass
  • c = specific heat = unknown
  • \Delta t = 82-30.5 = 51.5 = change in temperature

note: the symbol \Delta is the uppercase Greek letter delta. It represents the difference or change in a value.

Apply those values into the formula below. Solve for c.

Q = m*c*\Delta t\\\\714 = 52*c*51.5\\\\714 = 52*51.5*c\\\\714 = 2678*c\\\\2678*c = 714\\\\c = \frac{714}{2678}\\\\c \approx 0.26661687826737\\\\c \approx 0.267\\\\

The specific heat of the unknown metal is roughly 0.267 \frac{\text{J}}{\text{g}^{\circ}\text{C}}

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2. The given statement is false, Kc or equilibrium constant is a fixed quantity, while there can be a reduction or enhancement in the Q based upon the condition.  

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