Answer:
1,1,1
decomposition reaction
Explanation:
The reaction equation is given as:
_Ca(OH)₂ → _CaO + _H₂O
This reaction is a decomposition reaction in which a single reactant breaks down to give two or more products.
To balance the equation, we assign variables a, b and c, then we use a mathematical approach to solve the problem;
aCa(OH)₂ → bCaO + cH₂O
Conserving Ca : a = b
O: 2a = b + c
H: 2a = 2c
let a = 1, b = 1 , c = 1
Use the formula (P1V1)/T1 = (P2V2)/T2
(12.8 * 100)/(-108 + 273) = (.855 * P2)/(22 + 273) Need to convert Celsius into Kelvins
1280/165 = (0.855 * P2)/295
7.755556 = 0.002898 * P2
P2 = 2676.18 kPa
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Answer:
i think the answer is letter C. From 35°c to 45°c
Explanation:
sorry if it is wrong
Answer:
336.6 grams of CO₂ and 183.6 grams of H₂O are formed from 2.55 moles of propane.
Explanation:
In this case, the balanced reaction is:
C₃H₈ + 5 O₂ → 3 CO₂ + 4 H₂O
By stoichiometry of the reaction (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of reactant and product participate in the reaction:
- C₃H₈: 1 mole
- O₂: 5 moles
- CO₂: 3 moles
- H₂O: 4 moles
Being the molar mass of each compound:
- C₃H₈: 44 g/mole
- O₂: 16 g/mole
- CO₂: 44 g/mole
- H₂O: 18 g/mole
Then, by stoichiometry, the following quantities of mass participate in the reaction:
- C₃H₈: 1 mole* 44 g/mole= 44 grams
- O₂: 5 moles* 16 g/mole= 80 grams
- CO₂: 3 moles* 44 g/mole= 132 grams
- H₂O: 4 moles* 18 g/mole= 72 grams
So you can apply the following rules of three:
- If by stoichiometry 1 mole of C₃H₈ forms 132 grams of CO₂, 2.55 moles of C₃H₈ how much mass of CO₂ will it form?

mass of CO₂= 336.6 grams
- If by stoichiometry 1 mole of C₃H₈ forms 72 grams of H₂O, 2.55 moles of C₃H₈ how much mass of H₂O will it form?

mass of H₂O= 183.6 grams
<u><em>336.6 grams of CO₂ and 183.6 grams of H₂O are formed from 2.55 moles of propane.</em></u>