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3 years ago

Which scientist was involved in the War of Currents? Help

Physics

1 answer:

Nataliya [291]3 years ago

6 0

Explanation:

thomas edison and Nikola tesla were involved in the war of currents

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The Kelly family and the Garcia family each used their sprinklers last summer. The water output rate for the Kelly family's spri

elena55 [62]

Answer:

30 hours

15 hours.

Explanation:

Let the Kelly used sprinkler for t hours and Gracia used the sprinkler for the rest ie (45 - t) hours .

Water output by Kelly = (35 x t) L

Water output by Gracia = 20 ( 45 - t ) L

Total output = 35t + 20(45 - t)

So, 35 t + 20 (45 - t ) = 1350

35 t + 900 - 20 t = 1350

15 t = 450

t = 30 hours

So Kelly used sprinkler for 30 hours and Gracia used it for 45 - 30 = 15 hours.

3 0

3 years ago

A parallel plate capacitor can store

Norma-Jean [14]

A parallel plate capacitor can store electric charge and
electrical energy, and if the plates are far enough apart,
you can store your lunch in there too.

3 0

3 years ago

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A car is running at a velocity of 50 miles per hour and the driver accelerates the car by 10 miles per hour square.How far the c

krek1111 [17]

It will be 80 miles and it can be done only in 16 min

7 0

3 years ago

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Calculate the initial (from rest) acceleration of a proton in a 5.00 x 10^6 N/C electric field (such as created by a research Va

julsineya [31]

Answer:

Acceleration of the proton will be equal to $4.79\times 10^{14}m/sec^2$

Explanation:

We have given electric field $E=5\times 10^6N/C$

Mass of proton is equal to $m=1.67\times 10^{-27}kg$

And charge on proton is equal to $e=1.6\times 10^{-19}C$

Electrostatic force will be responsible for the motion of proton

Electrostatic force will be equal to $F=qE=1.6\times 10^{-19}\times 5\times 10^6=8\times 10^{-13}N$

According to newton law force on the proton will be equal to F = ma, here m is mass of proton and a is acceleration

This newton force will be equal to electrostatic force

So $1.67\times 10^{-27}\times a=8\times 10^{-13}$

$a=4.79\times 10^{14}m/sec^2$

So acceleration of the proton will be equal to $4.79\times 10^{14}m/sec^2$

5 0

3 years ago

A motorbike accelerates from 15m/s to 25m/s in 15 seconds.

RSB [31]

distance traveled by a uniformly accelerated bike is given as

$d = \frac{v_f + v_i}{2} (t)$

here we know that

$v_f = 25 m/s$

$v_i = 15 m/s$

$t = 15 s$

now we will have from above equation

$d = \frac{15 + 25}{2} (15)$

$d = 20 (15) = 300 m$

so it will cover the total distance of 300 m

5 0

3 years ago