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3 years ago

..............anybody knows this?

Physics

2 answers:

Natalija [7]3 years ago

6 0

Answer:

100 N right

Explanation:

Add 30 + 20 + 50 = 100

ioda3 years ago

3 0

Answer:

should be C

Explanation:

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Why are some areas in Europe seeing a partial solar eclipse while others are observing a total solar eclipse?

GuDViN [60]

Answer:

Objects between the source and observer produce possible shadows known as the umbra and the penumbra.

The umbra is a totally shadowed area, no light travels directly from the source to the observer.

The penumbra is a partially shadowed are where some of the source light travels directly to the observer an some of the source light is blocked from the observer (the object blocking the light is not a point object).

The question apparently refers to the differences seen by the observers.

5 0

3 years ago

Which of these is NOT a chemical property of matter?

marshall27 [118]

C. Magnetism

It is a physical property, not a chemical property.

7 0

3 years ago

•• Your roommate is working on his bicycle and has the bike upside down. He spins the 60-cm-diameter wheel, and you notice that

Y_Kistochka [10]

Answer:

$v=0.57\frac{m}{s}$

$a_c=10.83\frac{m}{s^2}$

Explanation:

We have an uniform circular motion, therefore, the pebble’s speed is given by the distance traveled in a revolution $(2\pi r)$ and the period (T), since this is the time pebble’s takes to complete a revolution:

$v=\frac{2\pi r}{T}$

The period is inversely proportional to the frequency:

$T=\frac{1}{f}$

So, we have:

$v=\frac{2\pi r}{\frac{1}{f}}\\v=2\pi rf\\$

Recall that the radius is the half of the diameter and one revolution per is equal to one Hz:

$v=2\pi (30*10^{-2}m)(3Hz)\\v=0.57\frac{m}{s}$

The centripetal acceleration is defined as:

$a_c=\frac{v^2}{r}\\a_c=\frac{(0.57\frac{m}{s})^2}{30*10^{-2}m}\\\\a_c=10.83\frac{m}{s^2}$

6 0

3 years ago

Active transport is a process that uses energy to move materials through a

Nat2105 [25]

Not good with this but I’m gonna guess cell membrane?

5 0

3 years ago

A potter spins his wheel at 0.98 rev/s. The wheel has a mass of 4.2 kg and a radius of 0.35 m. He drops a chunk of clay of 2.9 k

Bad White [126]

Answer:

$v_{f,w} = 1.791\,\frac{m}{s}$ , $v_{f,c} = 0.972\,\frac{m}{s}$

Explanation:

The situation can be modelled by applying the Principle of Angular Momentum Conservation:

$I_{w} \cdot \omega_{o} = (I_{w} + I_{c})\cdot \omega_{f}$

The final angular speed is:

$\omega_{f} = \frac{I_{w}}{I_{w}+I_{c}}\cdot \omega_{o}$

$\omega_{f} = \left(\frac{\frac{1}{2}\cdot (4.2\,kg)\cdot (0.35\,m)^{2} }{\frac{1}{2}\cdot (4.2\,kg)\cdot (0.35\,m)^{2} + \frac{1}{2}\cdot (2.9\,kg)\cdot (0.19\,m)^{2}}\right)\cdot (0.98\,\frac{rev}{s} )\cdot \left(\frac{2\pi\,rad}{1\,rev} \right)$

$\omega_{f} \approx 5.116\,\frac{rad}{s}$

The tangential velocities of the wheel and the clay are, respectively:

$v_{f, w} = (0.35\,m)\cdot (5.116\,\frac{rad}{s} )$

$v_{f,w} = 1.791\,\frac{m}{s}$

$v_{f, c} = (0.19\,m) \cdot (5.116\,\frac{rad}{s} )$

$v_{f,c} = 0.972\,\frac{m}{s}$

5 0

3 years ago