Question

Imagine a third particle, which we will call a cyberon. It has three times the mass of an electron (3m). It has a positive charge that is three times the magnitude (3qe) of the charge on an electron. What is the ratio of the speed vc that the cyberon would have when it reaches the upper plate after being released from rest at position h0 to the speed ve that the electron would have

Answer 1

Answer:

Explanation:

Let the potential difference between plate be V .

Electrical energy lost for cyberon = V x 3e

Kinetic energy lost by cyberon = kinetic energy gain by it

V x 3e = 1/2 x 3m x vc²

For electron , the above equation becomes

V x e = 1/2 x m x ve²

Dividing the two equations

1 = vc² / ve²

vc = ve .

vc / ve = 1 .