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2 years ago

What did Brother Guy say when he was showing all the pictures of scientists? (the basic point he was making)

Engineering

2 answers:

OverLord2011 [107]2 years ago

7 0

i’m gonna need some context here bud

77julia77 [94]2 years ago

6 0

Hopefully the other person helps you I’ll come back to see but I can’t right now

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A turboprop engine consists of a diffuser, compressor, combustor, turbine, and nozzle. The turbine drives a propeller as well as

Yuri [45]

Answer:

Power =10004.57kw

Velocity = 296.4m/s

Explanation:

Please see attachment

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3 years ago

You start your car and begin to pull out of a parking space. After leaving the space, You notice that the brake light on your in

saw5 [17]

If your brake lights are staying on, it will drain your battery.The most likely cause for the brake lights staying on is the brake light switch sticking closed. You can disconnect the plug from the brake light switch at the brake light pedal to see if the lights turn off.

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2 years ago

A rigid 10-L vessel initially contains a mixture of liquid and vapor water at 100 °C, with a quality factor of 0.123. The mixtur

masya89 [10]

Answer:

$Q_{in} = 46.454\,kJ$

Explanation:

The vessel is modelled after the First Law of Thermodynamics. Let suppose the inexistence of mass interaction at boundary between vessel and surroundings, changes in potential and kinectic energy are negligible and vessel is a rigid recipient.

$Q_{in} = U_{2} - U_{1}$

Properties of water at initial and final state are:

State 1 - (Liquid-Vapor Mixture)

$P = 101.42\,kPa$

$T = 100\,^{\textdegree}C$

$\nu = 0.2066\,\frac{m^{3}}{kg}$

$u = 675.761\,\frac{kJ}{kg}$

$x = 0.123$

State 2 - (Liquid-Vapor Mixture)

$P = 476.16\,kPa$

$T = 150\,^{\textdegree}C$

$\nu = 0.2066\,\frac{m^{3}}{kg}$

$u = 1643.545\,\frac{kJ}{kg}$

$x = 0.525$

The mass stored in the vessel is:

$m = \frac{V}{\nu}$

$m = \frac{10\times 10^{-3}\,m^{3}}{0.2066\,\frac{m^{3}}{kg} }$

$m = 0.048\,kg$

The heat transfer require to the process is:

$Q_{in} = m\cdot (u_{2}-u_{1})$

$Q_{in} = (0.048\,kg)\cdot (1643.545\,\frac{kJ}{kg} - 675.761\,\frac{kJ}{kg} )$

$Q_{in} = 46.454\,kJ$

3 0

2 years ago

Write the 5 important of profession education in a point

tensa zangetsu [6.8K]

did it help ? I was going to put the same things so

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2 years ago

Indicate on a tensile curve such quantities as yield stress, Young's modulus, UTS, toughness, point of necking, point of fractur

Illusion [34]

Explanation:

Step1

In the stress-strain curve of any material, the yield stress is the maximum stress at which material starts yielding.

Step2

Young’s modulus is the constant of proportionality of stress and strain according to hooks law. It is the slope of the slope of the stress-strain curve of the any material under proportional limit.

Step3

Ultimate tensile stress is the maximum stress that induced in the material under application of load.

Step4

Toughness is the strain energy per unit volume up to the fracture point of the stress-strain diagram of any material. This is the area under the curve of stress-strain.

Step5

Point of necking is the point where any material starts necking under application of load in necking region of the stress-strain curve.

Step6

Fracture point is the last point of the stress-strain curve where component fractures under application of load.

All the parameters are shown in below stress-strain curve:

8 0

3 years ago