g A pump is required to deliver 100 gpm at a head of 100 ft, but the pump rated capacity is 150 gpm at a head of 100 ft. If the
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To solve this problem it is necessary to apply the concepts related to temperature stagnation and adiabatic pressure in a system.
The stagnation temperature can be defined as
Where
T = Static temperature
V = Velocity of Fluid
Specific Heat
Re-arrange to find the static temperature we have that
Now the pressure of helium by using the Adiabatic pressure temperature is
Where,
= Stagnation pressure of the fluid
k = Specific heat ratio
Replacing we have that
Therefore the static temperature of air at given conditions is 72.88K and the static pressure is 0.399Mpa
<em>Note: I took the exactly temperature of 400 ° C the equivalent of 673.15K. The approach given in the 600K statement could be inaccurate.</em>
At equilibrium, the sum of clockwise and anticlockwise moments about a point is zero
The mass of that balances the system is kg
The normal reaction force at the fulcrum is <u>5,804.25 N</u>
Rason:
The mass of the stick = 150.0 g
Mass m₁ on the left = 50.0 g, location = 30 cm to the left of m₂
Mass m₂ on the left = 75.0 g, location = 40 cm to the left of the fulcrum
Mass m₃ on the right of the fulcrum. location = 30 cm to the right of the fulcrum
Required:
To find the mass of m₃
Solution:
Taking moment about the fulcrum, we have;
50 × (30 + 40) + 75 × (40) + 150 × 20 = m₃ × 30
9,500 = m₃×30
The mass of that balances the system when it is attached at the right end of the stick, m₃ = kg
Normal reaction at the fulcrum = (50 + 75 + 150 + ) × 9.81 = 5804.25
The normal reaction at the fulcrum is 5,804.25 N
Learn more about the moment of a force here:
