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2 years ago

14. The maximum amount a homeowner should spend on housing is

Engineering

1 answer:

Simora [160]2 years ago

8 0

Answer:

28%

Explanation:

Although there are sources that says 30% of gross income can be spent on housing, the most reliable amount that can be spent (according to other sources) is 28%.

Take for instance, you earn $5000 monthly, the maximum that you can spend on housing is:

$Max = 28\% * \$5000$

Using a calculator, we have:

$Max = \$1400$

<em>The maximum that can be spent on a monthly gross income of $5000 is $1400</em>

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LenaWriter [7]

Put them in 2,4,1,3 and got in 100 in the test

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3 years ago

The collapse of the magnetic field inside the ignition coil happens as a

Tanzania [10]

Primary coil

See an example below

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3 years ago

What is the proper distance from the feet of a straight ladder to the wall?

blondinia [14]

Answer:

One Foot

Explanation:

The general rule is to maintain a distance of one foot per four feet of height.

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3 years ago

A semiconductor diode has the following parameters: Is = 4.0×10-13 Amps, n = 1.35, and is operated at a temperature of T = 270K.

andrew-mc [135]

Answer:

$V_T=0.02328V\\I=7.77\times 10^{-5} A \\V_D=0.77V$

Explanation:

Let's use Shockley ideal diode equation which relates the current intensity and the potential difference:

$I=I_S (e^{\frac{V_D}{nV_T} } -1)$

Where:

$I=Diode\hspace{3}current\\I_S=Reverse\hspace{3}bias\hspace{3}saturation\hspace{3}current\\V_D=Voltage\hspace{3}across\hspace{3}the\hspace{3}diode\\V_T=Thermal\hspace{3}voltage\\n=Ideality\hspace{3}factor$

Thermal voltage at any temperature it is a known constant defined by:

$V_T=\frac{kT}{q}$

Where:

$k= Boltzmann\hspace{3}constant \approx1.38\times 10^{-23} \\T=Absolute\hspace{3}temperature\\q=Charge\hspace{3}of\hspace{3}an\hspace{3}electron \approx 1.6\times 10^{-19} C$

(a)

Using the data provided:

$V_T=\frac{(1.38\times 10^{-23})*(270) }{1.6\times 10^{-19} }= 0.0232875V$

(b)

Using the data provided and Shockley ideal diode equation

$I=(4\times 10^{-13} )*(e^{\frac{0.6}{1.35*0.0232875} }-1)=7.773505834\times10^{-5}\approx 7.77 \times10^{-5}A\\I\approx0.0777mA$

$I=I_S (e^{\frac{V_D}{nV_T} } -1)\\\\Multiply\hspace{3}both\hspace{3}sides\hspace{3}by\hspace{3}I_S\\\\\ \frac{I}{I_S} = e^{\frac{V_D}{nV_T} } -1\\\\Add\hspace{3}1\hspace{3}both\hspace{3}sides\\\\$

$\frac{I}{I_S} +1 =e^{\frac{V_D}{nV_T} } \\\\Take\hspace{3}the\hspace{3}natural\hspace{3}logarithm\hspace{3}of\hspace{3}both\hspace{3}sides\\\\\frac{V_D}{nV_T} =log(\frac{I}{I_S} +1) \\\\Multiply\hspace{3}both\hspace{3}sides\hspace{3}by\hspace{3}nV_T\\\\V_D=nV_T*log(\frac{I}{I_S} +1)$

Finally, using the data provided:

$V_D=(1.35)(0.0232875)*log(\frac{20\times 10^{-3} }{4\times 10^{-13} }+1)=0.77448729\approx 0.77V$

7 0

3 years ago

E total kinetic energy of a 2500 lbm car when it is moving at 80 mph (in BTU)?

Galina-37 [17]

Answer:

KE= 687.21 BTU

Explanation:

Given that

Mass of car = 2500 lbm

We know that 1 lb=0.45 kg

So the mass of car m =1133.98 kg

Velocity of car= 80 mph

We know that 1 mph =0.44 m/s

So velocity of car = 35.76 m/s

As we know that kinetic energy (KE) is given as follows

$KE=\dfrac{1}{2}mv^2$

Now by putting the values

$KE=\dfrac{1}{2}\times 1133.98\times 35.76^2$

KE=725.05 KJ

We know that 1 KJ = 0.94 BTU

So KE= 687.21 BTU

3 0

3 years ago