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LenaWriter [7]
3 years ago
11

14. The maximum amount a homeowner should spend on housing is

Engineering
1 answer:
Simora [160]3 years ago
8 0

Answer:

28%

Explanation:

Although there are sources that says 30% of gross income can be spent on housing, the most reliable amount that can be spent (according to other sources) is 28%.

Take for instance, you earn $5000 monthly, the maximum that you can spend on housing is:

Max = 28\% * \$5000

Using a calculator, we have:

Max = \$1400

<em>The maximum that can be spent on a monthly gross income of $5000 is $1400</em>

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Explain why slopping roofs are used in areas with heavy rain or snow fall
Savatey [412]

Answer:

Slopping or slanting roofs are found in houses where there are snow or rain, because it helps the water or the snow to skid down easily. It minimizes the chances of waterlogging because water cannot rest on the roof surface for long.

Explanation:

Brainliest pls.

8 0
3 years ago
An insulated piston-cylinder device contains 0.15 of saturated refrigerant-134a vapor at 0.8 MPa pressure. The refrigerant is no
Stells [14]

Answer:

Assumption:

1. The kinetic and potential energy changes are negligible

2. The cylinder is well insulated and thus heat transfer is negligible.

3. The thermal energy stored in the cylinder itself is negligible.

4. The process is stated to be reversible

Analysis:

a. This is reversible adiabatic(i.e isentropic) process and thus s_{1} =s_{2}

From the refrigerant table A11-A13

P_{1} =0.8MPa   \left \{ {{ {{v_{1}=v_{g}  @0.8MPa =0.025645 m^{3/}/kg } } \atop { {{u_{1}=u_{g}  @0.8MPa =246.82 kJ/kg } -   also  {{s_{1}=s_{g}  @0.8MPa =0.91853 kJ/kgK } } \right.

sat vapor

m=\frac{V}{v_{1} } =\frac{0.15}{0.025645} =5.8491 kg\\and \\\\P_{2} =0.2MPa  \left \{ {{x_{2} =\frac{s_{2} -s_{f} }{s_{fg }}=\frac{0.91853-0.15449}{0.78339}   = 0.9753 \atop {u_{2} =u_{f} +x_{2} }(u_{fg}) =  38.26+0.9753(186.25)= 38.26+181.65 =219.9kJ/kg \right. \\s_{1} = s_{2}

T_{2} =T_{sat @ 0.2MPa} = -10.09^{o}  C

b.) We take the content of the cylinder as the sysytem.

This is a closed system since no mass leaves or enters.

Hence, the energy balance for adiabatic closed system can be expressed as:

E_{in} - E_{out}  =ΔE

w_{b, out}  =ΔU

w_{b, out} =m([tex]u_{1} -u_{2)

w_{b, out}  = workdone during the isentropic process

=5.8491(246.82-219.9)

=5.8491(26.91)

=157.3993

=157.4kJ

4 0
3 years ago
The cost to become a member of a fitness center is as follows: the membership fee per month is $50.00 the personal training sess
NikAS [45]

Answer:

#include <iostream>

using namespace std;

void information(){

cout<<"Welcome to the portal"<<endl;

cout<<"The membership fee per month is $50.00"<<endl;

cout<<"The personal training session fee is $30.00"<<endl;

cout<<"The senior citizens discount is 30%"<<endl;

cout<<"If the membership is bought and paid for 12 or more months, the discount is 15%;"<<endl;

cout<<"If more than five personal training sessions are bought and paid for, the discount on each session is 20%."<<endl;

}

void getInfo(bool &senior, int &months, int &personal){

cout<<"Are you senior citizen y/n ? : ";

char choice;

cin>>choice;

if(choice=='y' || choice=='Y'){

senior = true;

}else{

senior = false;

}

cout<<"Enter number of months for membership : ";

cin>>months;

cout<<"Enter number of personal training session : ";

cin>>personal;

}

double calcCost(bool senior, int months, int personal){

double cost=0;

double memberShipCost=months*50;

double trainingCost=personal*30;

if(personal>5){

trainingCost*=.80; //discount on personal training

}

if(months>=12){

memberShipCost*=.85; //discount on membership

}

cost = memberShipCost+trainingCost;

//discount for seniors

if(senior){

cost = cost*.70;

}

return cost;

}

int main() {

information();

cout<<"Select an option"<<endl;

char choice;

while(true){

cout<<endl<<endl;

cout<<"a. Calculate membership costs."<<endl;

cout<<"b. Quit program."<<endl;

cout<<"Enter your choice : ";

cin>>choice;

bool senior=true;

int months,personal;

if(choice=='a'){

getInfo(senior,months,personal);

double cost=calcCost(senior, months, personal);

cout<<"The calculated cost is $"<<cost<<endl;

}else if(choice=='b'){

break;

}

}

return 0;

}

Explanation:

8 0
4 years ago
Write a Person class with a constructor that accepts the following details:
Liono4ka [1.6K]

The person class is an illustration of constructors;

In computer programs, constructors are automatically called when the object of a class is created

<h3>The program in C++</h3>

The class and the constructor program written in C++ programming language is as follows:

int main(){

   string fname, lname,dob,idno,mobileno;

   cin>>lname; cin>>fname; cin>>dob;  cin>>idno; cin>>mobileno;

Person c(fname,lname,dob,idno,mobileno);

if(mobileno.length() == 12){

    if(mobileno[3] == '-' && mobileno[7] == '-'){

        cout << "Name: " << c.getfname() << " " << c.getlname() << endl

 << "Date of birth: " << c.getdob() << endl

 << "ID number: " << c.getid() << endl

 << "Mobile: " << c.getmobile() << endl

 << "Age: "<< getAge(dob)<<endl;

 ;

    }

}

The complete program is added as an attachment

Read more about C++ programs at:

brainly.com/question/13168905

#SPJ1

Download cpp
3 0
2 years ago
Nitrogen (N2) contained in a piston–cylinder arrangement, initially at 10 bar and 405 K, undergoes an expansion to a final tempe
yKpoI14uk [10]

Answer:28.21 kJ/kg

Explanation:

Given

P_1=10\ bar

T_1=405\ K

T_2=300\ K

Process PV^{1.3}=constant

Work done for Polytropic process

W=\dfrac{P_1V_1-P_2V_2}{n-1}

where n=Polytropic index

W=\dfrac{R(T_1-T_2)}{n-1}

W=\dfrac{0.296(405-300)}{1.3-1}\quad [R_{N_2}=\frac{8.314}{28}]

W=103.6\ kJ\kg

Now Calculating change in Internal energy

\Delta U=c_v(T_2-T_1)

\Delta U=0.718\times (300-405)

\Delta U=-75.39\ kJ/kg

Now applying First law concept

\Delta U=Q-W

Q=W+\Delta U

Q=103.6-75.392

Q=28.21\ kJ/kg

6 0
4 years ago
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