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Law Incorporation [45]
3 years ago
15

How many electrons does a neutral atom of the element iron (fe) have?

Physics
1 answer:
borishaifa [10]3 years ago
3 0

Answer:

26 electrons

A neutral iron atom contains 26 protons and 30 neutrons plus 26 electrons in four different shells around the nucleus. As with other transition metals, a variable number of electrons from iron's two outermost shells are available to combine with other elements

Explanation:

hope this helps have a good rest of your night :) ❤

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Two gravitational forces act on a particle, in perpendicular directions. to find the net force, can we add the magnitudes of tho
Anna71 [15]

No, we can not add the magnitudes of those two forces.

<h3>What is Gravitational Force?</h3>

An attractive force between masses is a gravitational force. According to Isaac Newton's second law, F = ma, a gravitational force generates an acceleration just like all other forces do. Remember that according to Newton's second law, a body will accelerate if there is a net force acting on it in an inertial frame of reference (a coordinate system travelling at a constant speed). According to Newton's Universal Law of Gravitation, when two bodies, such as the Earth and the Sun, are in close proximity to one another, an attractive force naturally attracts them. This attraction results in an acceleration of the two objects. 

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6 0
2 years ago
Un zapato de golf tiene 10 tacos cada uno con un área de 0.01 pulgadas en contacto con el piso suponga que el camino hay un inst
iren2701 [21]

Responder:

12374550,527 N / m²

Explicación:

Dado que:

Número de tacos = 10

Área de cada montante = 0.01 in²

Peso total de la persona = 180 libras

Usando la relación:

Presión = Fuerza / Área

La fuerza ejercida es el producto de la masa y la aceleración debido a la gravedad.

Masa = 180 libras = 81,47 kg

Aceleración por gravedad = 9,8 m / s²

Área total = (número de montantes * Área por montante) = (10 * 0.01) = 0.1 pulg²

Conversión a m²:

0,1 pulg² = 6,452 * 10 ^ -5 m²

Por lo tanto,

Presión = (81,47 * 9,8) / (6,452 * 10 ^ -5)

Presión = 798.406 / 0.00006452

Presión = 12374550.527 N / m²

6 0
3 years ago
A 6.20 g bullet moving at 929 m/s strikes a 850 g wooden block at rest on a frictionless surface. The bullet emerges, traveling
nekit [7.7K]

Answer:

(a) Final speed of block = 3.2896 m/s

(b) 6.7350 m/s is the speed of the bullet-block center of mass?

Explanation:

Given that:

Mass of bullet (m₁) = 6.20 g

Initial Speed of bullet (u₁) = 929 m/s

Final speed of bullet (v₁) = 478 m/s

Mass of wooden block (m₂) = 850g

Initial speed of block initial (u₂) = 0  m/s

Final speed of block (v₂) = ?

<u>By the law of conservation of momentum  as:</u>

<u>m₁×u₁ + m₂×u₂ = m₁×v₁ + m₂×v₂</u>

6.20×929 + 850×0 = 6.20×478 + 850×v₂

Solving for v₂, we get:

<u>v₂ = 3.2896 m/s</u>

Let the V be the speed of the bullet-block center of mass. So,

V = [m₁* u₁]/[m₁ + m₂]  (p before collision = p after collision)

   = [6.2 *929]/[5.2+850]

<u>V = 6.7350 m/s </u>

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