Answer:
No.
Explanation:
We shall solve this problem by calculating the resolving power of eye for given wavelength
Resolving Power of eye = \frac{1.22\lambda }{D}
Where λ is wave length of light and D is diameter of eye.
λ is 600 nm and D is 3.5 mm . Put these values in the given formula
Resolving Power = \frac{1.22\times 600\times 10^{-9} }{3.5\times 10^{-3}}\\
=209.14 \times 10^{-6}radian
From the formula
Φ = \frac{L}{D}[/tex]
Where Ф is resolving power . If L be distance between two points that can be resolved at distance D. D is 6 km or 6000 m .
209.14 \times 10^{-6}=\frac{L}{6000}\\
L= 1.254 m
So minimum distance that can be resolved is 1.254 m.
Answer:
129.2 C
0.33758239177 mm
Explanation:
n = Number density = 
i = Current = 170 A
t = Time taken = 0.76 s
d = Diameter = 6 mm
Charge is given by
The charge passing throught the motor is 129.2 C
Current density
Drift velocity is given by
Distance traveled
The electron traveled 0.33758239177 mm
The resistance of the conductor is 0.07940 Ohms.
<h3>What is the relation between resistance and area of wire?</h3>
The wire's resistance is inversely related to its cross-sectional area; as the area drops, so does the resistance.
and it is formulated as:
where,
<em>p </em>- resistivity of the conductor (0.0214-ohm mm²/m)
R - resistance
l- length of conductor (50 feet) (15.24 m)
s - the area of the wire
Thus the resistance can be calculated as
R = 0.07940 Ohms.
Learn more about resistance here:
brainly.com/question/11431009
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Answer:
a) The voltage on resistor R1 is less than before. Letter B.
b) The current through R1 is less than before. Letter B.
c) The resistance of the circuit went up by adding R2 in series. Letter A.
Explanation:
a) The new resistor R2 was added in series, that means the same current goes through both resistors (R1 and R2) and that the sum of the individual voltage drop of those resistors should be the same as the voltage of the source. Before there was only resistor R1 connected to the source, so all the voltage of the source was being delivered to that component, but now it is divided between R1 and R2. So the voltage on R1 is less than previously. Letter B.
b) A battery works as a voltage source, so assuming it's charged, it delivers a value of voltage to the circuit, while the current flow through it is defined by the equivalent resistance across the terminals. Since the new resistor was added in series the total resistance of the circuit went up and the current delivered by the battery went down. Letter B.
c) Since the equivalent resistance for a series connection is the sum of the resistors, R12 = R1 + R2, the resistence went up. Letter A.
