A pendulum is formed by taking a 2kg mass and hanging it from the ceiling using a steel wire with a diameter of 1.1 mm. It is ob
served that the wire stretches by 0.05 mm under the weight of the mass. What is the period of oscillation of the pendulum?
1 answer:
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Answer:
Using the given values
F = K q^2 / r^2 = 9 * 10E9 * (1.6 * E-19)^2 / (5.18 * E-15)^2 N
E = 9 * 1.6^2 / 5.18^2 * 10 = 8.5 N
Answer:
25.632 m²
Explanation:
area = a*b
area = 3.2m * 8.01m
area = 25.632 m²
Hear is transferred from the heating elements to the Pot by Conductivity
Work = Force x Distance
Assuming that this work is being done parallel to the displacement that is, but under that assumption:
W = (50)(10)
W = 500 J
Answer:
.3 repeating hours
Explanation:
