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Ne4ueva [31]
3 years ago
13

A pendulum is formed by taking a 2kg mass and hanging it from the ceiling using a steel wire with a diameter of 1.1 mm. It is ob

served that the wire stretches by 0.05 mm under the weight of the mass. What is the period of oscillation of the pendulum?
Physics
1 answer:
Mekhanik [1.2K]3 years ago
5 0
Please elaborate more on your question so I can help you
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Please help quick please
Ede4ka [16]
I can’t see the picture what do you need help with
3 0
3 years ago
How many liters are in 0.034 moles of chlorine gas?
Anuta_ua [19.1K]

The volume of the gas is 7.6\cdot 10^{-4}m^3

Explanation:

At standard temperature and pressure (stp), the volume occupied by 1 mole of an ideal gas is always equal to

V=22.4 L

In this problem, we have an amount of moles of gas of

n = 0.034 mol

Since 1 mol of gas occupies a volume of 22.4 L, we can set up the following ratio:

\frac{1 mol}{22.4 L}=\frac{0.034 mol}{V}

where V is the volume occupied by 0.034 mol of gas. Solving for V, we find

V=\frac{0.034 mol}{1 mol}(22.4 L)=0.76 L

Or, in cubic metres,

V=0.76 L = 7.6\cdot 10^{-4}m^3

Learn more about ideal gases:

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3 0
4 years ago
The grounded conductor and the grounding conductor are one and the same conductor and perform the same function.
STALIN [3.7K]

Answer:

Grounded  used to carry the current in the normal conditions. while on the other side grounding is refer to that safety wire that is connected to the earth and currently does not transmit through it.

As grounding wire is referred to as safety wire hence it carries current only in an emergency like a short circuit.

Explanation:

A grounded conductor is referred to as one of the wire that needed in an electric circuit. it is basically a neutral conductor.  It used to carry the current in the normal conditions. while on the other side grounding is refer to that safety wire that is connected to the earth and currently does not transmit through it.

As grounding wire is referred to as safety wire hence it carries current only in an emergency like a short circuit.

5 0
3 years ago
Calculate the wavelength and frequency at which the intensity of the radiation is a maximum for a blackbody at 298 K. You will n
Juliette [100K]

Answer:

Wavelength, \lambda=9.72\times 10^{-6}\ m

Frequency, f=3.08\times 10^{13}\ Hz

Explanation:

We need to find the intensity of the radiation is a maximum for a black body at 298 K. It can be calculated using Wein's displacement law. It is given by :

\lambda T=2.898\times 10^{-3}\ m-K

\lambda=\dfrac{2.898\times 10^{-3}}{T}

Here, T = 298 K

\lambda=\dfrac{2.898\times 10^{-3}}{298}

\lambda=9.72\times 10^{-6}\ m

If f is the frequency of black body radiation. It is given by :

f=\dfrac{c}{\lambda}

f=\dfrac{3\times 10^8}{9.72\times 10^{-6}}

f=3.08\times 10^{13}\ Hz

Hence, this is the required solution.                                              

6 0
3 years ago
How many atoms of each element are in the chemical formula P205?
Irina-Kira [14]

2 atoms of P (phosphorus) and 5 atoms of O (oxygen)

Explanation:

The chemical formula of a generic compound is written as

A_n B_m

where

A and B are the symbols of the elements contained in the compound

n and m are the number of atoms of each element, A and B respectively

In this problem, the compound given is

P_2 O_5

where:

- P is the symbol of the chemical element phosphorus

- O is the symbol of the chemical element oxygen

We see that the number following P is 2, so there are 2 atoms of phosphorus, while the number following O is 5, so there are 5 atoms of oxygen.

Learn more about compounds here:

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5 0
4 years ago
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