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dlinn [17]
3 years ago
12

Identify three movements during which the instantaneous angular velocity at a particular time is the quantity of interest. Expla

in your choices.
Physics
1 answer:
wlad13 [49]3 years ago
8 0

Answer:

Explanation:

Angular velocity is rate of change of angular displacement with respect to time.

\omega =\frac{\mathrm{d} \theta }{\mathrm{d} t}

Examples of instantaneous

  1. Finding instantaneous angular velocity of a point of rotating wheel  of car with certain linear velocity.
  2. The slope of angular displacement and  time graph gives the value of instantaneous angular velocity
  3. Finding angular velocity of merry go round wheel          
You might be interested in
A car of weight 6,400 N has four wheels. Each wheel has an area of
Natasha2012 [34]

Answer:

80N/cm^2

Explanation:

Given data

A car of weight 6,400N

Area= 80cm^2

The weight is distributed evenly on the 4 wheels

hence 6400/4

=1600 N

We know that

Pressure = force/Area

Pressure= 1600/80

Pressure= 20 N/cm^2

For the four wheels, the pressure is

=20*4

=80N/cm^2

6 0
3 years ago
The father of scientific management is- (
Ilia_Sergeevich [38]
I think it is d but not sure

4 0
4 years ago
What is the speed of an aardvark that runs 10 meters every hour?
VashaNatasha [74]

Answer:

10m/hr

Explanation:

10m/3600 sec= 1m/360sec

8 0
3 years ago
A lawn mower engine running for 20 m i n does 4, 5 6 0, 0 0 0 J of work. What is the power output of the engine?
VladimirAG [237]

Answer:3800\ W

Explanation:

Given

Lawn mover running for t=20\ min

and does W=4560\times 10^3\ J

We know Power is rate of work i.e.

P=\frac{\text{Work}}{\text{time}}

P=\frac{4560\times 10^3}{20\times 60}

P=3800\ W

Thus Power output is 3800\ W

4 0
3 years ago
A 600kg car is at rest, and then it accelerates to 5 m/s.
uranmaximum [27]

Answer:

1. 0 J

2. 7500 J

3. 7500 J

Explanation:

From the question given above, the following data were obtained:

Mass (m) of car = 600 Kg

Initial velocity (v₁) of car = 0 m/s

Final velocity (v₂) of car = 5 m/s

Original kinetic energy (KE₁) =?

Final kinetic energy (KE₂) =?

Work used =?

1. Determination of the original kinetic energy.

Mass (m) of car = 600 Kg

Initial velocity (v₁) of car = 0 m/s

Original kinetic energy (KE₁) =?

KE₁ = ½mv₁²

KE₁ = ½ × 600 × 0²

KE₁ = 0 J

Thus, the original kinetic energy of the car is 0 J.

2. Determination of the final kinetic energy.

Mass (m) of car = 600 Kg

Final velocity (v₂) of car = 5 m/s

Final kinetic energy (KE₂) =?

KE₂ = ½mv₂²

KE₂ = ½ × 600 × 5²

KE₂ = 300 × 25

KE₂ = 7500 J

Thus, the final kinetic energy of the car is 7500 J

3. Determination of the work used.

Original kinetic energy (KE₁) = 0

Final kinetic energy (KE₂) = 7500 J

Work used =?

Work used = KE₂ – KE₁

Work used = 7500 – 0

Work used = 7500 J

6 0
3 years ago
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