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3 years ago

An object's weight is what to it's mass

Physics

1 answer:

oee [108]3 years ago

5 0

object's weight is the independent of mass and gravity .

Weight = mass × gravity

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A bullet traveling at 350 m/s hits a tree, penetrating 0.125 m into the tree before stopping. The mass of the bullet is 0.200 kg

Sloan [31]

Answer:

$-4.9\cdot 10^5 m/s^2$

Explanation:

The motion of the bullet is a uniformly accelerated motion, therefore we can find its acceleration by using the following suvat equation:

$v^2-u^2=2as$

where

v is the final velocity

u is the initial velocity

a is the acceleration

s is the distance covered

For the bullet in this problem:

u = 350 m/s is the initial velocity of the bullet

v = 0 is the final velocity (the bullet comes to a stop)

s = 0.125 m is the stopping distance of the bullet

Therefore, by solving the equation for a, we find its acceleration:

$a=\frac{v^2-u^2}{2s}=\frac{0^2-350^2}{2(0.125)}=-4.9\cdot 10^5 m/s^2$

And the negative sign tells that the direction of the acceleration is opposite to that of the velocity.

7 0

4 years ago

6. For a cell to produce a current, the

Reil [10]

Answer:

for a cell to produce a current the cell electrodes of the cell must have a potential difference option A is the correct answer

6 0

2 years ago

Read 2 more answers

a stone is thrown horizonttaly from a cliff of a hill with an initial velocity of 30m/s it hits the ground at a horizontal dista

ELEN [110]

Answer:

a) Time = 2.67 s

b) Height = 35.0 m

Explanation:

a) The time of flight can be found using the following equation:

$x_{f} = x_{0} + v_{0_{x}}t + \frac{1}{2}at^{2}$ (1)

Where:

$x_{f}$ : is the final position in the horizontal direction = 80 m

$x_{0}$ : is the initial position in the horizontal direction = 0

$v_{0_{x}}$ : is the initial velocity in the horizontal direction = 30 m/s

a: is the acceleration in the horizontal direction = 0 (the stone is only accelerated by gravity)

t: is the time =?

By entering the above values into equation (1) and solving for "t", we can find the time of flight of the stone:

$t = \frac{x_{f}}{v_{0}} = \frac{80 m}{30 m/s} = 2.67 s$

b) The height of the hill is given by:

$y_{f} = y_{0} + v_{0_{y}}t - \frac{1}{2}gt^{2}$

Where:

$y_{f}$ : is the final position in the vertical direction = 0

$y_{0}$ : is the initial position in the vertical direction =?

$v_{0_{y}}$ : is the initial velocity in the vertical direction =0 (the stone is thrown horizontally)

g: is the acceleration due to gravity = 9.81 m/s²

Hence, the height of the hill is:

$y_{0} = \frac{1}{2}gt^{2} = \frac{1}{2}9.81 m/s^{2}*(2.67 s)^{2} = 35.0 m$

I hope it helps you!

5 0

3 years ago

The distance measured from trough to trough or crest to crest of a wave is called the

ikadub [295]

Its called a wavelength

7 0

3 years ago

Read 2 more answers

Please show work on how to get to the answer. When the diameter of a vessel is increased by 2 times, the flow will :

Sonja [21]

Answer:

(a) Increase 16 times

Explanation:

According to the Poiseuille flow equation the rate of flow of fluid is directly related to four time square of the radius of the vessel.

$F\alpha r^{4}$

Here, F is the rate of flow, and r is the radius of vessel.

Now according to the question diameter is increased by 2 times then radius is also increased by two times than radius becomes 2r.

So put this value in the flow equation.

$F\alpha (2r)^{4}\\F\alpha 16r^{4}$

Therefore, the rate of flow is increased by 16 times.

6 0

3 years ago