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Leya [2.2K]
3 years ago
8

An object's weight is what to it's mass

Physics
1 answer:
oee [108]3 years ago
5 0

object's weight is the independent of mass and gravity .

Weight = mass × gravity

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D because choppy water is already a little bit of wave action and then the wind adds a lot of speed to the waves and height to the waves to meek the best waves. Hope this helped.
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A well blended mixture that contains at least one solute and one solvent is a _____.
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A solution, an example is salt and water. brainliest?
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A wave transfers _____ from the source outward in the direction of wave motion.
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To add, <span>in physics, a </span>wave<span> is an oscillation accompanied by a transfer of energy that travels through a medium (space or mass). Frequency refers to the addition of time.</span>

5 0
3 years ago
A 6.2 kg ladder, 1.97 m long, rests on two sawhorses. Sawhorse A is 0.64 m from one end of the ladder, and sawhorse B is 0.17 m
Keith_Richards [23]

Answer:

42.69 N and 18.07 N

Explanation:

We are given that

Mass of ladder=6.2 kg

Length of ladder=1.97 m

Distance of Sawhorse A from one end=0.64 m

Distance of sawhorse B from other end=0.17 m

Let center of Ladder=\frac{1.97}{2}=0.985 m

Now, the distance of sawhorse A from center=r=0.985-0.64=0.345 m

Distance of sawhorse B from center of ladder=0.985-0.17=0.815  m

Force one ladder due to gravity=mg=6.2\times 9.8=60.76N

Where g=9.8 m/s^2

Torque applied on Sawhorse A=0.345F_a

Torque applied on Sawhorse B=0.815F_b

In equilibrium

0.345F_a=0.815F_b

F_b=\frac{0.345}{0.815}F_a

Total force=F_a+F_b

F_a+\frac{0.345}{0.815}F_a=60.76

\frac{0.815F_a+0.345F_a}{0.815}=60.76

\frac{1.16}{0.815}F_a=60.76

F_a=\frac{60.76\times 0.815}{1.16}=42.69 N

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8 0
3 years ago
An electron de-excites from the fourth quantum level to the third and then directly to the first. Two frequencies of light are e
4vir4ik [10]

Answer:

The answer is explained below.

Explanation:

The energy emitted during the de-excitation of an electron from a higher energy level to a lower energy level is directly proportional to the frequency of the emitted light.

Here, the total sum of the energies of 2 frequencies of light emitted in different stages is equal to the energy of a single frequency of light during the de-excitation of fourth level to ground level directly.

Hence the total sum of of the frequencies of 2 lights emitted in different stages is equal to the frequency of single frequency of light emitted during the de-excitation  from fourth level to ground level directly.

The some of the energies of 2 frequencies emitted by one electron is equal to the energy of a single frequency when electron jumps directly.

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