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Leya [2.2K]
3 years ago
8

An object's weight is what to it's mass

Physics
1 answer:
oee [108]3 years ago
5 0

object's weight is the independent of mass and gravity .

Weight = mass × gravity

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5. An undisturbed soil sample has a wet density of 2.5 Mg/m3 when the water content is 25%. The specific gravity of the soil par
Dima020 [189]

Answer:

The submerged effective density is 86.93 kN/m³ or 8.693 Mg/m³

Explanation:

Given;

wet density of soil sample = 2.5 Mg/m³ = 25 kN/m³

Specific gravity of solid particle = 2.7

The dry unit weight of soil;

\gamma _d = \frac{\gamma _t}{1 +w} = \frac{25}{1+0.25} = 20 \ kN/m^3

for undisturbed state, the volume of the soil is;

V_s =\frac{\gamma _d}{G_s \gamma _w} = \frac{20}{2.7*9.81} = 0.76 \ m^3\\\\Void \ volume, V_v = 1-0.76 = 0.24 \ m^3

Void \ ratio, \ e = \frac{0.24}{0.76} = 0.32

Submerged effective density is given as;

\rho _b = \frac{\rho_w(\gamma_s -1)}{1+e}

density of water (ρw) = 2.7 x 25 kN/m³ = 67.5 kN/m³, substitute this in the above equation;

\rho _b = \frac{\rho_w(\gamma_s -1)}{1+e} =  \frac{67.5(2.7 -1)}{1+0.32} = 86.93 \ kN/m^3

Therefore, the submerged effective density is 86.93 kN/m³ or 8.693 Mg/m³

5 0
3 years ago
You perform an experiment to measure the speed of a car over time. The results are shown in the graph below. What is the best in
lora16 [44]

Hi i also need help but i cant seem to get it

3 0
3 years ago
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Which statement describes how nuclear power generation systems work?
galben [10]

Answer:

c- heat for electricity generation process comes from nuclear fission

Explanation:

nuclear fission is splitting of atoms to release energy held at nucleus of atoms

4 0
2 years ago
To pull a nail out of a wood board a carpenter does 1000 J of work. The hammer he uses does 835 J of work. What is the efficienc
saw5 [17]

Answer:

83.5%

Explanation:

7 0
3 years ago
A student in an undergraduate physics lab is studying Archimede's principle of bouyancy. The student is given a brass cylinder a
Readme [11.4K]

Answer:

V = 0.3724 m³

T = 27.836 N

Explanation:

Given :

m = 3.21 kg  , W= 3.21 * 9.81 m / s² = 31.4901 N

ρ = 8.62 g / cm ³  = 8620 kg / m³

V = m / ρ =  3.21 kg  /  8620 kg / m³

V = 0.3724 m³

when submerged the weight of brass cylinder is equal to the tension in string:

F =  (0.3724m³) * (1000 kg / m³) * (9.81 m/s²²) = 3.653 ≈ 3.65 N

T = 31.4901 N - 3.65 N  

T = 27.836 N

3 0
3 years ago
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