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MatroZZZ [7]
3 years ago
14

If mass remains the same while the volume of a substance ________, the density of the substance will_______________. decreases,

decrease increases, decrease increases, stay the same decreases, stay the same
Physics
2 answers:
gtnhenbr [62]3 years ago
7 0
Density =Mass/volume
When mass is constant, density is inversely proportional to volume or vice versa
When volume decreases, density increases
Hope it helps
Katyanochek1 [597]3 years ago
5 0

Answer:

2. increases, decrease

Explanation:

The density of any object is given by the formula:

Density=\frac{mass}{volume}

So if you have constant mass, and an increase on volume, the prodcut of dividing the same amount of mass by more volume will be a direct decrease on the density of the object, the same if you keep the mass but reduce the volume, as you have the same mass in less volume, the result would be an increase in density.

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If a bike is traveling at 12 km/hr for 20 minutes how far will it travel
geniusboy [140]
1) 20 min = 1/3 h
2) distance = speed * time = 12 * 1/3 = 4 km

3 0
3 years ago
10 PTS.
gayaneshka [121]

1.2 x (2.2 x 10⁵) = 264,000 Ω

0.8 x (2.2 x 10⁵) = 176,000 Ω

With a 'nominal' value of 220,000 Ω, it could actually be anywhere <em>between 176,000Ω and 264,000Ω</em> .

8 0
3 years ago
An electron is accelerated by a 5.9 kV potential difference. das (sd38882) – Homework #9 – yu – (44120) 3 The charge on an elect
klio [65]

Complete Question

An electron is accelerated by a 5.9 kV potential difference. das (sd38882) – Homework #9 – yu – (44120) 3 The charge on an electron is 1.60218 × 10−19 C and its mass is 9.10939 × 10−31 kg. How strong a magnetic field must be experienced by the electron if its path is a circle of radius 5.4 cm?

Answer:

The magnetic field strength is  B= 0.0048 T

Explanation:

The work done by the potential difference on the electron is related to the kinetic energy of the electron by this mathematical expression

                             \Delta V q = \frac{1}{2}mv^2

      Making v the subject

                             v = \sqrt{[\frac{2 \Delta V * q }{m}] }

 Where m is the mass of electron

              v is the velocity of electron

              q charge on electron

               \Delta V is the potential difference  

Substituting values

         v = \sqrt{\frac{2 * 5.9 *10^3 * 1.60218*10^{-19} }{9.10939 *10^{-31]} }f

            = 4.5556 *10^ {7} m/s

For the electron to move in a circular path the magnetic force[F = B q v] must be equal to the centripetal force[\frac{mv^2}{r}] and this is mathematically represented as

                  Bqv = \frac{mv^2}{r}

making B the subject

                B = \frac{mv}{rq}

r is the radius with a value = 5.4cm = = \frac{5.4}{100} = 5.4*10^{-2} m

Substituting values

                B = \frac{9.1039 *10^{-31} * 4.556 *10^7}{5.4*10^-2 * 1.60218*10^{-19}}

                     = 0.0048 T

                 

7 0
4 years ago
Striking a match stick on the matchbox involves the reaction of potassium chlorate and red phosphorus with the following equatio
yarga [219]

Answer:

m(P4) =  46.175 (grams)

m (KClO3) = 149 (grams)


Explanation:

1) n(P4) = n(P4O10);

m(P4)/M(P4) = m(P4O10)/M(P4O10);

m(P4) = M(P4)*m(P4O10)/M(P4O10)
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2) Analogously, 10n(P4O10) = 3n(KClO3)

m (KClO3) = 10M(KClO3)*m(P4O10)/3M(P4O10)
                = 10*122.55*105.8/283.89/3
                = 149 (grams).

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