Answer:
Explanation:
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Answer:
450g of coke (C)
Explanation:
Step 1:
The balanced equation for the reaction is given below:
3C(s) + 2SO2(g) —> CS2(s) + 2CO2(g)
Step 2:
Determination of the mass of C that reacted and the mass of CS2 produced from the balanced equation.
This is illustrated below:
Molar Mass of C = 12g/mol
Mass of C from the balanced equation = 3 x 12 = 36g
Molar Mass of CS2 = 12 + (32x2) = 12 + 64 = 76g/mol.
From the balanced equation above, 36g of C reacted to produce 76g of CS2.
Step 3:
Determination of the mass of C required to produce 950g of CS2. This is illustrated below:
From the balanced equation above, 36g of C reacted to produce 76g of CS2.
Therefore, Xg of C will react to produce 950g of CS2 i.e
Xg of C = (36 x 950)/76
Xg of C = 450g
From the calculations made above, 450g of coke (C) is needed to produce 950g of CS2.
The reaction that releases energy as heat is called an Exothermic reaction. This reaction does obey the law of conservation by preserving the energy present in the molecule and converting it to thermal heat to maintain it's from. Most reactions obey the law of conservation of energy.
Can you post the question
Answer:
C₆H₆
Explanation:
We need to find the molecular formula of a compound of carbon (C) and hydrogen (H), so what <em>we need to find out is the number of atoms of C and of H in the molecule.</em> We know:
- molar mass = 78.1 g/mol
- C% = 92.3% = 92.3 g C / 100 g compound
So, in 1 mol of compound, 92.3% of the mass corresponds to Carbon:
<u>mass of C / mol of compound</u> = molar mass × C% = 78.1 g/mol × 92.3/100 = <u>72.1 g/mol</u>
<u>moles of C</u> = mass C / molar mass C = 72.1 g / 12.011 g/mol
moles of C = 6 moles of C per mol of compound
If 72.1 g in a mol of compound are Carbon atoms, the difference between the molar mass and the mass of Carbon atoms will correspond to H atoms in 1 mol of compound:
<u>mass of H / mol of compound</u> = molar mass - mass of C/mol
mass of H = 78.1 g / mol - 72.1 g /mol = <u>6.0 g/mol of compound</u>
<u>moles of H</u> = mass H / molar mass H = 6.0 g / 1.008 g/mol
moles of H = 6.0 moles of H per mol of compound
<em>So</em><em> one mol of compound has 6 moles of C and 6 moles of H.</em>
The molecular formula is then written as C₆H₆
