<u>Answer:</u> The correct option is C) 1.68 mol/L
<u>Explanation:</u>
Molarity is defined as the amount of solute expressed in the number of moles present per liter of solution. The units of molarity are mol/L. The formula used to calculate molarity:
.....(1)
Given values:
Given mass of 
= 150 g
Molar mass of = 180 g/mol
Volume of the solution = 0.50 L
Putting values in equation 1, we get:
Hence, the correct option is C) 1.68 mol/L
Okay
Mr (H2O)= 18g
therefore moles of H2O
is 720.8/18= 40.04mol
the ratio of H2 to O2 to H2O is
2 : 1 : 2
so moles of H2 is same as H2O here
H2= 40.04moles
moles of O2 is half
so 40.04 x 0.5
20.02moles
grams of O2 is
its moles into Mr of O2
that's 20.02 x 32 = 640.64g
Answer:
Sound waves travelling through the air: Sound waves travelling through air are just like longitudinal waves lacking compressions and rarefactions. The speed of sound waves in air is approximately 332 metres per second.
Light waves travelling through air: Light waves travel in air at a much faster rate than sound waves. Light waves can travel with a speed of 300 000 kilometres per second through air.
Sound waves traveling through metal: Sound waves travel about 17 times faster in metal as compared to air. The sound waves travel with an approximate speed of 5,960 meters per second in metals.
Light waves travelling through metal: The speed of light waves in a metal medium is usually at a net speed which is less than 3.00 x 108 m/s.
Light travels faster than sound waves because light waves are not pressure waves like the sound waves. They also do not require a medium as the sound waves.
Oxidizing agent is that which is reduced and the reducing agent is that which is oxidized. Reduced is when the charged is decreased and oxidized when the charge is increased.
(1) 2Na + 2H2O(l) --> 2NaOH(aq) + H2(g)
The charge of Na in the reactant is 0 and the charge of Na in the NaOH is +1. Na is oxidized. Hence, it is the reducing agent.
The charge of H in H2O is +1 while that in H2 is 0. H is reduced. Hence, it is the oxidizing agent.
(2) C(s) + O2(g) --> CO2(g)
The charge of C in the reactant side is 0 and that its charge in CO2 is +4. C is oxidized. Hence, it is the reducing agent.
The charge of O in O2 is 0 while in CO2, its charge is -2. O is reduced. Hence, it is the oxidizing agent.
(3) 2MnO⁻⁴ + SO2 + 2H2O --> 2Mn²⁺ + 5SO2⁻⁴ 4H⁺
The charge of Mn in MnO⁻⁴ is 4+ while its charge in Mn²⁺ is 2+. Mn is reduced. Hence, it is the oxidizing agent.
The charged of S in SO2 is -4 while its charge in SO₂⁻⁴ is 0. S is oxidized. Hence, it is the reducing agent.
Answer:
b) The two pieces of tape will repel as both have obtained a static charge.
this is the right answer.
Explanation:
