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ladessa [460]
3 years ago
11

A gas has a volume of 31.2 L at a temperature of 28 degrees Celsius and a pressure of 82.6 kPa. How many moles are in the sample

of gas?
Under what conditions do gases deviate from ideal behavior?
high pressure and high temperatures
high pressure and low temperatures
low pressure and low temperatures
low pressure and high temperatures
Chemistry
1 answer:
zhenek [66]3 years ago
5 0

1.02 moles of the gas is present in the sample.

The conditions in which the gases deviate from ideal behavior is high pressure and low temperatures.

Correct option is 2.

Explanation:

Data given:

volume of the gas = 31.2 litres

temperature of the gas = 28 degrees or 301.15 K

pressure of the gas = 82.6 kPa or 0.815 atm

R (Gas constant) = 0.0820 Latm/moles K

number of moles =?

From the ideal gas law, we have

PV = nRT

rearranging the equation:

n = \frac{PV}{RT}

n = \frac{0.815 X 31.2}{301.15 X 0.0820}

n = 1.02 moles

At high pressure and low temperature an ideal gas deviates from ideal behaviour. Under high pressure the gas molecules get closer to each other and intermolecular force acts on them as molecules attract each other while in ideal case gas has no attractions in its molecules.

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The reaction of glucose, c6h12o6, with oxygen produces carbon dioxide and water. what is the sum of the coefficients in the bala
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What is Gram Atomic mass ?​
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2 years ago
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opper(I) ions in aqueous solution react with NH 3 ( aq ) according to Cu + ( aq ) + 2 NH 3 ( aq ) ⟶ Cu ( NH 3 ) + 2 ( aq ) K f =
Y_Kistochka [10]

Answer:

55.373g/l

Explanation:

The dissolved amount of sparingly soluble salts is interlinked with a unitlesss quantity called as solubility product. It is a fixed quantity that only increases with the rise in temperatures and is used to predict the salting out of compounds. If the value of ionic product (Q) is larger than (Ksp), precipitation of compound occurs.

Given:

The solubility product of CuBr is 6.3×10−9.

The concentration of NH3 is 0.10 M.

Formula and Calculations:

The dissolution reaction (I) of CuBr is shown below.

The reaction showing dissolution of CuBr in NH3 is shown below.

The above reaction can be obtained by adding reaction (I) and (II) as shown below.

The equilibrium constants will get multiplied.

Suppose the solubility of CuBr is “s”.

It is given that concentration of NH3 is 0.10 M.

The equilibrium constant expression for the above reaction is as follows,

Here,

The concentration of pure solids is 1 M. Thus, the concentration of CuBr is 1 M.

As calculated, the value of Ksp is 396.9.

Substitute all the required values in above formula.  

On further solving above equation,

Therefore, the solubility of CuBr in ammonia is 0.386 M.

The formula to calculate solubility

Solubuility (g/l)= Molarity(M) x Molarmass

Chemistry homework question answer, step 2, image 10

The molar mass of CuBr is 143.45 g/mol.

The formula to calculate solubility in g/L is given below.

The molar mass of CuBr is 143.45 g/mol.

therefore,

solubility = 0.386M x 143.45g/mol

where (M = mol/l)

solubility = 55.375g/l

5 0
3 years ago
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