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3 years ago

Find the length a. a=?

Mathematics

1 answer:

algol [13]3 years ago

6 0

Cosine law
a²=b²+c²-2ab*cosA

a²=13²+11²-2*13*11*cos(108)≈378.37
a≈19.45

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Help me please!! The next model of a sports car will cost 12.2% less than the current model. The current model costs $34,000. Ho

andrey2020 [161]

Answer:

the price will decrease by 4148

the price of the next model will be 29852

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3 years ago

What are the steps for this inequality: 6z < 48

cestrela7 [59]

Answer:

z<8

Step-by-step explanation:

First: write down the equation : 6z<48

Second: divide both sides with 6 (since its the only number that can be divided for both sides)

Third: then you'll get z<8

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3 years ago

Can somebody do this

yuradex [85]

Answer:

1/4

Step-by-step explanation:

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8 0

3 years ago

Read 2 more answers

Please help solve this system of equations

stepan [7]

Make a substitution:

$\begin{cases}u=2x+y\\v=2x-y\end{cases}$

Then the system becomes

$\begin{cases}\dfrac{2\sqrt[3]{u}}{u-v}+\dfrac{2\sqrt[3]{u}}{u+v}=\dfrac{81}{182}\\\\\dfrac{2\sqrt[3]{v}}{u-v}-\dfrac{2\sqrt[3]{v}}{u+v}=\dfrac1{182}\end{cases}$

Simplifying the equations gives

$\begin{cases}\dfrac{4\sqrt[3]{u^4}}{u^2-v^2}=\dfrac{81}{182}\\\\\dfrac{4\sqrt[3]{v^4}}{u^2-v^2}=\dfrac1{182}\end{cases}$

which is to say,

$\dfrac{4\sqrt[3]{u^4}}{u^2-v^2}=\dfrac{81\times4\sqrt[3]{v^4}}{u^2-v^2}$

$\implies\sqrt[3]{\left(\dfrac uv\right)^4}=81$

$\implies\dfrac uv=\pm27$

$\implies u=\pm27v$

Substituting this into the new system gives

$\dfrac{4\sqrt[3]{v^4}}{(\pm27v)^2-v^2}=\dfrac1{182}\implies\dfrac1{v^2}=1\implies v=\pm1$

$\implies u=\pm27$

Then

$\begin{cases}x=\dfrac{u+v}4\\\\y=\dfrac{u-v}2}\end{cases}\implies x=\pm7,y=\pm13$

(meaning two solutions are (7, 13) and (-7, -13))

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3 years ago

Write the equation for 5x + 2y = 3 in slope-intercept form.<br> 11

Nastasia [14]

5x+2y=3
-5x on both sides
2y=3-5x
divide by 2 on both sides
y=3/2-5/2x
rewrite in order (optional depending on teacher)
y=-5/2x+3/2

6 0

3 years ago