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atroni [7]
3 years ago
15

3 In the section describing protozoa, the author states: "Protozoa are germs that live in almost all soil, including the hot des

ert sand. They live in all water too. The reader can infer that protozoa can be found where? A only in oceans and on beaches B never in bodies all water and most soil mostly in warm climates​
Chemistry
1 answer:
Gnesinka [82]3 years ago
7 0

Answer:

I believe the answer is A.

Explanation:

This section states that protozoa live in all bodies of water therefore B can not be an answer because it says protozoa dose not live in any body of water.

I hope this answers your question.

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Willie has fewer than normal bacteria in his gut microbiome. How will this affect his health?
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Indegestion I believe as there isn't as much bacteria to break down his food.

Explanation:

Tbh, dont complain if you don't like a food, because when you chew it, its gonna turn into some white mush anyways, and when it comes out, its brown.

Dont blame me, blame your tooth.

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PLS PLS PLS PLS HELP IM STRUGGLING
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A. 4 only

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4 0
4 years ago
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4 0
4 years ago
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Using the appropriate ksp value from appendix d in the textbook, calculate the ph of a saturated solution of ca(oh)2 .
Alex777 [14]
The ph of a saturated solution of Ca(OH)2 is 12.35

CALCULATION:
For the reaction 
     Ca(OH)2 → Ca2+ + 2OH- 
we will use the Ksp expression to solve for the concentration [OH-] and then use the acid base concepts to get the pH:
     Ksp = [Ca2+][OH-]^2

The listed Ksp value is 5.5 x 10^-6. Substituting this to the Ksp expression, we have
     Ksp = 5.5 x 10^-6 = (s) (2s)^2 = 4s^3
     s3 = 5.5x10^-6 / 4

Taking the cube root, we now have
     s = cube root of (5.5x10^-6 / 4)s
        = 0.01112

We know that the value of [OH-] is actually equal to 2s:
     [OH-] = 2s = 2 * 0.01112 = 0.02224 M

We can now calculate for pOH:          
     pOH = - log [OH-]
              = -log(0.02224)
              = 1.65

Therefore, the pH is
     pH = 14 - pOH
           = 14 - 1.65
           = 12.35
4 0
4 years ago
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