The molarity of the diluted solution is 0.33 M
From the question given above, the following data were obtained:
Molarity of stock solution (M₁) = 0. 5 M
Volume of stock solution (V₁) = 100 mL
Volume of diluted solution (V₂) = 100 + 50 = 150 mL
<h3>Molarity of diluted solution (M₂) =? </h3>
The molarity of the diluted solution can be obtained by using the dilution formula as illustrated below:
<h3>M₁V₁ = M₂V₂</h3>
0.5 × 100 = M₂ × 150
50 = M₂ × 150
Divide both side by 150
M₂ = 50 / 150
<h3>M₂ = 0.33 M</h3>
Therefore, the molarity of the diluted solution is 0.33 M
Learn more: brainly.com/question/24625656
Answer:
T = 82 K
Explanation:
The computation of the final temperature is shown below;
Given that
T_0 denotes the initial temperature of the gas i.e. 74 K
T denotes the final temperature of the gas = ?
n denotes number of moles of monoatomic gas i.e. 1.00 mol
R denotes universal gas constant = 8.314
c denotes the heat capacity at constant volume i.e.
= (1.5) R = (1.5) (8.314)
= 12.5
Q denotes the Amount of heat absorbed i.e 100 J
We know that
Amount of heat absorbed is provided as
Q = n c (T - T_0)
100 = (1) (12.5) (T - 74)
T = 82 K
Answer:
The final temperature of the system is 42.46°C.
Explanation:
In this problem we assumed that heat given by the hot body is equal to the heat taken by the cold body.
where,
c = specific heat of water= 
= mass of water sample with 100 °C= 50.0 g
= mass of water sample with 13.7 °C= 100.0 g
= final temperature of system
= initial temperature of 50 g of water sample= 
= initial temperature of 100 g of water =
Now put all the given values in the given formula, we get
The final temperature of the system is 42.46°C.
Answer:
3.74 atmospheres
Explanation:
If the temperature is constant, then the formula is
V*P = V1 * P1
V = 22.6 L
P = 1.67 atm
V1 = 10.0 L
P1 = ??
=============
22.6 * 1.67 = 10 * P1
37.742 = 10 * P1
37.742/10 = P1
P1 = 3.742
Note there are 3 sig digs in each given, so the answer should be
P1 = 3.74 atmospheres
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