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kompoz [17]
3 years ago
8

What is the ball's velocity after 0.500, 1.80, 2.90, and 4.00 s?

Physics
1 answer:
zhenek [66]3 years ago
4 0
The answer is 21 that is it 

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Describe the electron's path in this field. Describe the electron's path in this field. The electron will move in a clockwise ci
Jlenok [28]

Answer: D - The electron will move in a counterclockwise circular path if viewed in the direction of the magnetic field.

Explanation:

When the electron enters the field at an angle to the field direction the resulting path of the electron will be helical. Such motion occurs above the poles of the Earth where charges particles from the Sun spiral through the Earth's field to produce the aurorae.

Magnetic force on an electron = BILsinØ = B[e/t][vt] = BevØ

where v is the electron velocity

In a magnetic field the force is always at right angles to the motion of the electron (Fleming's left hand rule) and so the resulting path of the electron is circular.

4 0
3 years ago
The asteroid belt circles the sun between the orbits of mars and jupiter. one asteroid has a period of 5.0 earth years. assume a
My name is Ann [436]
Using Kepler's 3rd law which is: T² = 4π²r³ / GM 
Solved for r : 
r = [GMT² / 4π²]⅓ 
Where G is the universal gravitational constant,M is the mass of the sun,T is the asteroid's period in seconds, andr is the radius of the orbit.
Change 5.00 years to seconds : 
5.00years = 5.00years(365days/year)(24.0hours/day)(6... = 1.58 x 10^8s 
The radius of the orbit then is computed:
r = [(6.67 x 10^-11N∙m²/kg²)(1.99 x 10^30kg)(1.58 x 10^8s)² / 4π²]⅓ = 4.38 x 10^11m 
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Which of the following statements is true of the exception for informed consent
NeX [460]
What are the options? You did list them.
6 0
3 years ago
A car travelled a distance of 200 m with initial velocity of 216 km/hr. Calculate the acceleration
pogonyaev

Answer:

a = 16\ m/s^2

Explanation:

When the velocity changes uniformly, the object has a constant acceleration. The acceleration, the velocities, and the distance are related by the equation:

v_f^2=v_o^2+2ax

Where:

vf = final velocity

vo = initial velocity

a = acceleration

x = distance

Solving for a:

\displaystyle a=\frac{v_f^2-v_o^2}{2x}

The car travels a distance of x=200 m and the velocities are:

vo = 216 Km/h

vf = 360 Km/h

Both velocities must be converted to meters by seconds.

vo = 216 Km/h *1000/3600 = 60 m/s

vf = 360 Km/h *1000/3600 = 100 m/s

The acceleration is:

\displaystyle a=\frac{100^2-60^2}{2*200}

\displaystyle a=\frac{10000-3600}{400}

\displaystyle a=\frac{6400}{400}

\mathbf{a = 16\ m/s^2}

7 0
3 years ago
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