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stira [4]
3 years ago
5

Help me out :,( I’m just trying to graduate

Mathematics
2 answers:
sleet_krkn [62]3 years ago
7 0

Answer:

(-6,-5)=> f(x)= x^2-2x-5

(8,11)=> f(x)=3x+5

(3,2)=> f(x)=4-x

(6,28)=> f(x)=(x+5) x^2

Step-by-step explanation:

For f(x)=3x+5

Putting the values of domain one by one:

Putting x=1:

f(x)=3(1)+5

=3+5

=8

Putting x = 2:

f(x)=3(2)+5

=6+5  

=11

For function f(x)= x^2-2x-5

Putting x=1:

f(x)=〖(1)〗^2-2(1)-5

=1-2-5

= -6

Putting x=2

f(x)=〖(2)〗^2-2(2)-5

=4-4-5

= -5

For f(x)=(x+5) x^2

Putting x=1  

f(x)=(1+5) (1)^2

=6*1

=6

Putting x=2  

f(x)=(2+5) (2)^2

=7*4

=28

For f(x)=4-x

Putting x = 1

f(x)=4-1

=3

Putting x=2

f(x)=4-2

=2

So the ranges belonging to the functions when domain is (1,2) are:

(-6,-5)=> f(x)= x^2-2x-5

(8,11)=> f(x)=3x+5

(3,2)=> f(x)=4-x

(6,28)=> f(x)=(x+5) x^2

Masja [62]3 years ago
6 0

Whats your question

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8 0
2 years ago
Read 2 more answers
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Alex787 [66]
First you need to see that this is a quadratic. I need.to put all of the values on one side of equation to see what I got.
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Now this one is difficult to factor so i will use quadratic equation:
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we know that a b and c are in a quadratic at these positions.
ax^2 + bx + c

so
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split into the + and - for 2 answers
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And
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those are.the 2 answers

But but it says largest so -1/2
4 0
3 years ago
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