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3 years ago

Help me out :,( I’m just trying to graduate

Mathematics

2 answers:

sleet_krkn [62]3 years ago

7 0

Answer:

(-6,-5)=> f(x)= x^2-2x-5

(8,11)=> f(x)=3x+5

(3,2)=> f(x)=4-x

(6,28)=> f(x)=(x+5) x^2

Step-by-step explanation:

For f(x)=3x+5

Putting the values of domain one by one:

Putting x=1:

f(x)=3(1)+5

=3+5

Putting x = 2:

f(x)=3(2)+5

=6+5

=11

For function f(x)= x^2-2x-5

Putting x=1:

f(x)=〖(1)〗^2-2(1)-5

=1-2-5

= -6

Putting x=2

f(x)=〖(2)〗^2-2(2)-5

=4-4-5

= -5

For f(x)=(x+5) x^2

Putting x=1

f(x)=(1+5) (1)^2

=6*1

Putting x=2

f(x)=(2+5) (2)^2

=7*4

=28

For f(x)=4-x

Putting x = 1

f(x)=4-1

Putting x=2

f(x)=4-2

So the ranges belonging to the functions when domain is (1,2) are:

(-6,-5)=> f(x)= x^2-2x-5

(8,11)=> f(x)=3x+5

(3,2)=> f(x)=4-x

(6,28)=> f(x)=(x+5) x^2

Masja [62]3 years ago

6 0

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