What is the volume of 1 mole of gas at standard temperature and pressure

How many grams of lithium hypochlorite (LiClO) are there in 0.594 moles?

Flauer [41]

Answer : The mass of lithium hypochlorite are, 34.7 grams.

Explanation : Given,

Moles of $LiClO$ = 0.594 g

Molar mass of $LiClO$ = 58.4 g/mol

Expression used :

$\text{ Mass of }LiClO=\text{ Moles of }LiClO\times \text{ Molar mass of }LiClO$

Now put all the given values in this expression, we get:

$\text{ Mass of }LiClO=(0.594moles)\times (58.4g/mole)$

$\text{ Mass of }LiClO=34.7g$

Therefore, the mass of lithium hypochlorite are, 34.7 grams.

3 0

4 years ago

Which of the following best explains why the atomic theory changed over the past 200 years?

Marianna [84]

The atomic theory changed because as time passed by our technolgy has been improving our ability to find answers to these theories.

5 0

3 years ago

Read 2 more answers

a boy pulls a wagon with a force of 6 N east as another boy pushes it with a force of 4 N east. what is the net force?

Nesterboy [21]

Sum of the forces in the x direction = 6N - 4N = 2 Newtons East

7 0

4 years ago

Read 2 more answers

The mass of Mg in Mg (OH)2 in its 10.2 gms is

maksim [4K]

Answer:

<h3>The answer is 4.22g</h3>

Explanation:

To calculate the mass of Mg in the sample we must find the molar mass of Mg divide it by the molar mass of the sample and multiply it by the total mass of the sample

Molar mass (M) of Mg = 24g/mol

M of Mg (OH)2 = 24 + 2( 16 + 1)

= 24 + 34

= 58g/mol

Mass of Mg in Mg (OH)2 is

$\frac{24}{58} \times 10.2g \\ = 4.22g$

Hope this helps you.

6 0

3 years ago

Given the following: [G3P] = 1.5x10-5M; [BPG] = 3.0x10-3M ; [NAD+] = 1.2x10-5M; [NADH]=1.0x10-4 ; [HPO42-]= 1.2x10-5 M; pH = 7.5

mel-nik [20]

<u>Answer:</u> The given reaction is non-spontaneous in nature.

<u>Explanation:</u>

To calculate the $H^+$ concentration, we use the equation:

$pH=-\log[H^+]$

We are given:

pH of the solution = 7.5

$7.5=-\log [H^+]$

$[H^+]=10^{-7.5)=3.1\times 10^{-8}M$

For the given chemical equation:

$\text{Glyceraldehyde3-phosphate }+NAD^++HPO_4^{2-}\rightarrow \text{1,3-Biphosphoglycerate }+NADH+H^+$

The equation used to Gibbs free energy of the reaction follows:

$\Delta G=\Delta G^o+RT\ln K_{eq}$

where,

$\Delta G$ = free energy of the reaction

$\Delta G^o$ = standard Gibbs free energy = 6.3 kJ/mol = 6300 J/mol (Conversion factor: 1kJ = 1000J)

R = Gas constant = 8.314J/K mol

T = Temperature = $25^oC=[273+25]K=298K$

$K_{eq}$ = Ratio of concentration of products and reactants = $\frac{[BPG][NaDH][H^+]}{[G_3P][NAD^+][HPO_4^{2-}]}$

$[BPG]=3.0\times 10^{-3}M$

$[NADH]=1.0\times 10^{-4}M$

$[H^+]=3.1\times 10^{-8}M$

$[G_3P]=1.5\times 10^{-5}M$

$[NAD^+]=1.2\times 10^{-5}M$

$[HPO_4^{2-}]=1.2\times 10^{-5}M$

Putting values in above equation, we get:

$\Delta G=6300J/mol+(8.314J/K.mol\times 298K\times \ln (\frac{(3.0\times 10^{-3})\times (1.0\times 10^{-4})\times (3.1\times 10^{-8})}{(1.5\times 10^{-5})\times (1.2\times 10^{-5})\times (1.2\times 10^{-5})}))\\\\\Delta G=9917.02J/mol=9.92kJ/mol$

For the reaction to be spontaneous, the Gibbs free energy of the reaction must come out to be negative.

As, the Gibbs free energy of the reaction is positive. The reaction is said to be non-spontaneous.

Hence, the given reaction is non-spontaneous in nature.

4 0

3 years ago