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3 years ago

Is mountain lions a herbivore

2 answers:

7 0

Mountain lion have to hunt other animals up in the Mountains. Other animals are meat. Therefore mountain lions are carnivores, not herbivores.

I hope this helped!
If it did I would like it if I got brainliest :)

klemol [59]3 years ago

7 0

Carnivore - eats other animals.
Herbivore- eats only plants

So, no the moutain lion is not a herbivore, it is an carnivore, it stalks it's prey and feeds off of flesh.

-Hope this helps.

You might be interested in

Write the formula for each compound (the composition is given after each name):

erastovalidia [21]

Aluminum bromide should be written as AlBr₃ since we are told that there are 3 atoms of Br for every atom of Al.

I hope this helps. Let me know if anything is unclear.

3 0

3 years ago

Your lab partner named this compound 3-methyl-4-n-propylhexane, but that is not correct.

loris [4]

Answer: The correct IUPAC name of the alkane is 4-ethyl-3-methylheptane

Explanation:

The IUPAC nomenclature of alkanes are given as follows:

Select the longest possible carbon chain.
For the number of carbon atom, we add prefix as 'meth' for 1, 'eth' for 2, 'prop' for 3, 'but' for 4, 'pent' for 5, 'hex' for 6, 'sept' for 7, 'oct' for 8, 'nona' for 9 and 'deca' for 10.
A suffix '-ane' is added at the end of the name.
If two of more similar alkyl groups are present, then the words 'di', 'tri' 'tetra' and so on are used to specify the number of times these alkyl groups appear in the chain.

We are given:

An alkane having chemical name as 3-methyl-4-n-propylhexane. This will not be the correct name of the alkane because the longest possible carbon chain has 7 Carbon atoms, not 6 carbon atoms

The image of the given alkane is shown in the image below.

Hence, the correct IUPAC name of the alkane is 4-ethyl-3-methylheptane

4 0

3 years ago

What is the only part of an atom that cannot change (either protons, neutrons, or electrons)?

d1i1m1o1n [39]

The number of protons never changes in an atom. More electrons means a negative charge and fewer means a positive charge. Once an atom has an electrical charge it is called an ion. In an ion the atomic number and atomic mass do not change from the original.

3 0

3 years ago

To what temperature must a sample of nitrogen at 27°C and 0.625 atm be taken so that it’s pressure becomes 1.125 atm at constant

Karo-lina-s [1.5K]

Answer:

The sample of nitrogen must be taken to 267 $^{0}\textrm{C}$ .

Explanation:

Let's assume nitrogen gas behaves ideally.

Here amount of nitrogen gas in both states remain constant.

So, in accordance with combined gas law for a given amount of an ideal gas in two different states: $\frac{P_{1}V_{1}}{T_{1}}=\frac{P_{2}V_{2}}{T_{2}}$

where $P_{1}$ and $P_{2}$ are initial and final pressure respectively. $V_{1}$ and $V_{2}$ are initial and final volume respectively. $T_{1}$ and $T_{2}$ are initial and final temperature (in kelvin scale) respectively.

Here $V_{1}=V_{2}$ , $P_{1}=0.625atm$ , $T_{1}=(273+27)K=300K$ and $P_{2}=1.125atm$

So $T_{2}=\frac{P_{2}T_{1}}{P_{1}}=\frac{(1.125atm)\times (300K)}{(0.625atm)}=540K$

540 K = (540-273) $^{0}\textrm{C}$ = 267 $^{0}\textrm{C}$

So the sample of nitrogen must be taken to 267 $^{0}\textrm{C}$ .

8 0

3 years ago

Sound and light are both found as (4)

Mrrafil [7]

Answer:

Waves; wavelength; electromagnetic energy; ultraviolet light.

Explanation:

Sound are mechanical waves that are highly dependent on matter for their propagation and transmission.

Sound travels faster through solids than it does through either liquids or gases.

Lightwave can be defined as an electromagnetic wave that does not require a medium of propagation for it to travel through a vacuum of space where no particles exist.

Hence, sound and light are both found as waves, with a variety of wavelengths. The sun, a source of light waves specifically, releases a type of electromagnetic energy. It can be found as UVA or UVB types. These lights give off different levels of ultraviolet light, some of which can be harmful.

Additionally, the ultraviolet spectrum is divided into three categories and these are; UVA, UVB ,and UVC.

7 0

3 years ago