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Rom4ik [11]
3 years ago
7

A net force of 79 N causes a mass to accelerate at a rate of 3 m/s2. Determine the mass

Physics
1 answer:
zmey [24]3 years ago
4 0
Force= mass x acceleration

79=mass(3)

m=79/3

m=26.3 kg
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The "escape velocity" from Earth (the speed required to escape Earth's gravity) is 2.5 × 104 miles per hour. What is this speed
ANEK [815]

Answer:

2.5 × 10⁴ mi/h = 1.1 × 10⁴ m/s

Explanation:

Hi there!

We have the following equivalencies:

1 mile = 1609 m

1 hour = 3600 s

Then to convert miles to meters, we can multiply the given quantity in miles by ( 1609 m/ 1 mile) and we will obtain the same quantity in meters. In the same way, if we want to convert hours into seconds, we can multiply the given quantity in hours by (3600 s/ 1 hour) and we will obtain seconds.

Let´s convert miles per hour into m/s:

2.5*10^{4} \frac{mi}{h}  (\frac{1609m}{1mi})(\frac{1h}{3600s}) = 1.1 × 10⁴ m/s  (notice how the units mi and h cancel)

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3 years ago
The H-R diagram is based on what two criteria?
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4 0
3 years ago
Read 2 more answers
An ion's position vector is initially r = 8.0 i - 4.0 j + 3.0 k, and 8.0 s later it is r = 4.0 i + 8.0 j - 6.0 k, all in meters.
tangare [24]

The average velocity = Displacement between two points/ Time taken for that displacement

In this case An ion's position vector is initially r = 8.0 i - 4.0 j + 3.0 k, and 8.0 s later it is r = 4.0 i + 8.0 j - 6.0 k

So, displacement = 4.0 i + 8.0 j - 6.0 k - (8.0 i - 4.0 j + 3.0 k)

                             = -4.0 i + 12.0 j - 9.0 k

So velocity, V = (-4.0 i + 12.0 j - 9.0 k)/8

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So average velocity during 8 seconds = -0.5 i + 1.5 j - 1.125 k

3 0
3 years ago
Why do some scientists not use controlled experiments?
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7 0
4 years ago
A slender rod is 90.0 cm long and has mass 0.120 kg. A small 0.0200 kg sphere is welded to one end of the rod, and a small 0.080
deff fn [24]

Answer:

Speed of 0.08 kg mass when it will reach to the bottom position is 1.94 m/s

Explanation:

When rod is released from rest then due to unbalanced torque about the hinge the system will rotate

Now moment of inertia of the system is given as

I = \frac{ML^2}{12} + \frac{m_1L^2}{4} + \frac{m_2L^2}{4}

now we have

M = 0.120 kg

m_1 = 0.02 kg

m_3 = 0.08 kg

now we have

I = \frac{0.120(0.90)^2}{12} + \frac{0.02(0.90)^2}{4} + \frac{0.08(0.90)^2}{4}

so we have

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I = 0.02835

now by energy conservation we can say work done by gravity must be equal to change in kinetic energy

so we have

\frac{1}{2}I\omega^2 = m_1g \frac{L}{2} - m_2 g\frac{L}{2}

\frac{1}{2}(0.02835)\omega^2 = (0.08 - 0.02)(9.81)(0.45)

\omega = 4.32 rad/s

Now speed of 0.08 kg mass when it reaches to bottom point is given as

v = \omega \frac{L}{2}

v = 4.32 (0.45)

v = 1.94 m/s

3 0
4 years ago
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