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lukranit [14]
3 years ago
7

Technician A says powdered metal rods can be resized just like a regular rod. Technician B says powdered metal rods can be resiz

ed if bearings of a larger diameter are available for that particular engine. Who is correct?
Engineering
1 answer:
telo118 [61]3 years ago
8 0

Answer:

Technician B is correct

Explanation:

To resize a connecting rod’s big end, the bolts are removed and the cap and rod mating surfaces will be ground to an approximate measurement. Thereafter, the rod cap will be bolted back onto the rod while the bore is machined back to it's proper size. However, the challenge with powdered metal rods is that due to the fact that the fractured surface is critical to their alignment, they cannot tolerate having those surfaces ground smooth. Hence, they cannot be resized, except bearing inserts of larger diameters are available for that particular engine.

Thus, technician B is correct.

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Explanation:

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In a surface grinding operation, the wheel diameter = 8.0 in, wheel width = 1.0 in, wheel speed = 6000 ft/min, work speed = 40 f
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Explanation:

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We have a tube with a diameter of 5 inches that is 1 foot long. The tube then reduces the diameter to 3 inches. According to the
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2 years ago
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A cylindrical drill with radius 4 is used to bore a hole through the center of a sphere of radius 5. Find the volume of the ring
ANTONII [103]

Answer:

The volume of the ring shaped solid that remains is 21 unit^3.

Explanation:

The total volume of the sphere is given as:

Volume of Sphere = (4/3)πr^3

where, r = radius of sphere

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Volume of Sphere = 523.6 unit^3

Now, we find the volume of sphere removed by the drill:

Volume removed = (Cross-sectional Area of drill)(Diameter of Sphere)

Volume removed = (πr²)(D)

where, r = radius of drill = 4

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Therefore,

Volume removed = (π)(4)²(10)

Volume removed = 502.6 unit^3

Therefore, the volume of ring shaped solid that remains will be the difference between the total volume of sphere, and the volume removed.

Volume of Ring = Volume of Sphere - Volume removed

Volume of Ring = 523.6 - 502.6

<u>Volume of Ring = 21 unit^3</u>

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3 years ago
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