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Lunna [17]
3 years ago
9

In a surface grinding operation, the wheel diameter = 8.0 in, wheel width = 1.0 in, wheel speed = 6000 ft/min, work speed = 40 f

t/min, infeed = 0.002 in, and crossfeed = 0.20 in. The number of active grits per square inch of wheel surface = 400. Determine
(a) the average length per chip,
(b) the metal removal rate
(c) the number of chips formed per unit and the average volume per chip?
(d) If the tangential cutting force on the workpiece is 50 lb, what is the specific energy calculated for this job?
Engineering
1 answer:
Katen [24]3 years ago
7 0

Answer: the answer will be d because it is the right one to be

Explanation:

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A strain gauge with a 5 mm gauge length gives a displacement reading of 1.25 um. Calculate the stress value given by this displa
KengaRu [80]

Answer:

stress  = 50MPa

Explanation:

given data:

Length of strain guage is 5mm

displacement\delta = 1.25 \mu m =\frac{1.25}{1000} =  0.00125 mm

stress due to displacement in structural steel can be determined by using following relation

E =\frac{stress}{strain}

stress = E \times strain

where E is young's modulus of elasticity

E for steel is 200 GPa

stress = 200\times 10^3 *\frac{1.25*10^{-3}}{5}

stress  = 50MPa

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Explanation:

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3 years ago
What are the 5 major forest types?
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1. Equatorial Evergreen or Rainforest

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4 0
4 years ago
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Select the correct answer.<br> Which equation gives you the amount of work performed?
Fantom [35]

Answer:

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4 years ago
Oil with a density of 800 kg/m3 is pumped from a pressure of 0.6 bar to a pressure of 1.4 bar, and the outlet is 3 m above the i
Naddik [55]

Answer:

23.3808 kW

20.7088 kW

Explanation:

ρ = Density of oil = 800 kg/m³

P₁ = Initial Pressure = 0.6 bar

P₂ = Final Pressure = 1.4 bar

Q = Volumetric flow rate = 0.2 m³/s

A₁ = Area of inlet = 0.06 m²

A₂ = Area of outlet = 0.03 m²

Velocity through inlet = V₁ = Q/A₁ = 0.2/0.06 = 3.33 m/s

Velocity through outlet = V₂ = Q/A₂ = 0.2/0.03 = 6.67 m/s

Height between inlet and outlet = z₂ - z₁ = 3m

Temperature to remains constant and neglecting any heat transfer we use Bernoulli's equation

\frac {P_1}{\rho g}+\frac{V_1^2}{2g}+z_1+h=\frac {P_2}{\rho g}+\frac{V_2^2}{2g}+z_2\\\Rightarrow h=\frac{P_2-P_1}{\rho g}+\frac{V_2^2-V_1^2}{2g}+z_2-z_1\\\Rightarrow h=\frac{(1.4-0.6)\times 10^5}{800\times 9.81}+\frac{6.67_2^2-3.33^2}{2\times 9.81}+3\\\Rightarrow h=14.896\ m

Work done by pump

W_{p}=\rho gQh\\\Rightarrow W_{p}=800\times 9.81\times 0.2\times 14.896\\\Rightarrow W_{p}=23380.8\ W

∴ Power input to the pump 23.3808 kW

Now neglecting kinetic energy

h=\frac{P_2-P_1}{\rho g}+z_2-z_1\\\Righarrow h=\frac{(1.4-0.6)\times 10^5}{800\times 9.81}+3\\\Righarrow h=13.19\ m\\

Work done by pump

W_{p}=\rho gQh\\\Rightarrow W_{p}=800\times 9.81\times 0.2\times 13.193\\\Rightarrow W_{p}=20708.8\ W

∴ Power input to the pump 20.7088 kW

6 0
3 years ago
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