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larisa [96]
2 years ago
8

We have a tube with a diameter of 5 inches that is 1 foot long. The tube then reduces the diameter to 3 inches. According to the

Venturi effect, what will happen to the velocity of the fluid flowing through this section? What will happen to the pressure?
Engineering
2 answers:
Ksju [112]2 years ago
6 0
Can I get a picture? Of the question so I can understand it more?
NemiM [27]2 years ago
5 0
Can we get a Picture?
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The crash rate per mile is.
Colt1911 [192]

Answer:

75 percent

Explanation:

8 0
3 years ago
You have been assigned to design an open cylindrical storage tank 4 meters tall with a diameter of 8 meters to be made out of A-
Katen [24]

Answer:

The required wall thickness is 1.506 \times 10^{-3} m

Explanation:

Given:

Fluid density \rho = 1200 \frac{kg}{m^{3} }

Diameter of tank d = 8 m

Length of tank l = 4 m

F.S = 4

For A-36 steel yield stress \sigma = 250 MPa,

Allowable stress \sigma _{allow} = \frac{\sigma}{F.S}

 \sigma _{allow} = \frac{250}{4} = 62.5 MPa

Pressure force is given by,

 P = \rho gh

 P = 1200 \times 9.8 \times 4

P = 47088 Pa

Now for a vertical pipe,

\sigma _{allow} = \frac{Pd}{4t}

Where t = required thickness

 t = \frac{Pd}{4 \sigma _{allow} }

 t = \frac{47088 \times 8 }{4 \times 62.5 \times 10^{6} }

t = 1.506 \times 10^{-3} m

Therefore, the required wall thickness is 1.506 \times 10^{-3} m

8 0
3 years ago
Fill in the blank to correctly complete the statement below.
ZanzabumX [31]
Did not engineer cables factoring wind shear
4 0
3 years ago
Air is compressed in a reversible, isothermal, steady- flow process from 15 psia, 100°F to 100 psia. Calculate the work of compr
mixas84 [53]

Answer:

|W|=169.28 KJ/kg

ΔS = -0.544 KJ/Kg.K

Explanation:

Given that

T= 100°F

We know that

1 °F = 255.92 K

100°F = 310 .92 K

P _1= 15 psia

P _1= 100 psia

We know that work for isothermal process  

W=mRT\ln \dfrac{P_1}{P_2}

Lets take mass is 1 kg.

So work per unit mass

W=RT\ln \dfrac{P_1}{P_2}

We know that for air R=0.287KJ/kg.K

W=RT\ln \dfrac{P_1}{P_2}

W=0.287\times 310.92\ln \dfrac{15}{100}

W= - 169.28 KJ/kg

Negative sign indicates compression

|W|=169.28 KJ/kg

We know that change in entropy at constant volume

\Delta S=-R\ln \dfrac{P_2}{P_1}

\Delta S=-0.287\ln \dfrac{100}{15}

ΔS = -0.544 KJ/Kg.K

3 0
3 years ago
Techm digital definition comprises of
KonstantinChe [14]

Answer:

Below is the response to the given question:

Explanation:

The relevant services supplied through TechMahindra Digital Services Provider are among the different options given in n inquiry. This is a digital company that has offered its customers an end-to-end solution that digitalizes all the requirements for client operations. It offers digital solutions, services cloud-based, digital marketing strategies, and then all client needs.

8 0
3 years ago
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