Answer:
The required wall thickness is
m
Explanation:
Given:
Fluid density

Diameter of tank
m
Length of tank
m
F.S = 4
For A-36 steel yield stress
MPa,
Allowable stress 
MPa
Pressure force is given by,


Pa
Now for a vertical pipe,

Where
required thickness


m
Therefore, the required wall thickness is
m
Did not engineer cables factoring wind shear
Answer:
|W|=169.28 KJ/kg
ΔS = -0.544 KJ/Kg.K
Explanation:
Given that
T= 100°F
We know that
1 °F = 255.92 K
100°F = 310 .92 K

We know that work for isothermal process

Lets take mass is 1 kg.
So work per unit mass

We know that for air R=0.287KJ/kg.K


W= - 169.28 KJ/kg
Negative sign indicates compression
|W|=169.28 KJ/kg
We know that change in entropy at constant volume


ΔS = -0.544 KJ/Kg.K
Answer:
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Explanation:
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