Answer:
D) the bending of a wave as it moves around an obstacle or passes through a narrow opening
Explanation:
Even though light travels in straight line, it will bend around objects if their size is comparative to its wavelength. This phenomenon is called diffraction.
Light will also bend if the light travels from one medium to another medium at an angle, but that is called refraction.
Diffraction occurs in one medium. Refraction occurs when light travels from one medium to another.
Complete Question
The complete question is shown on the uploaded image
Answer:
The tension on the shank is ![T =8391.6 N](https://tex.z-dn.net/?f=T%20%3D8391.6%20N)
Explanation:
From the question we are told that
The strain on the strain on the head is ![\Delta l = 0.1 mm/mm = \frac{0.1}{1000} = 0.1 *10^{-3} m/m](https://tex.z-dn.net/?f=%5CDelta%20l%20%3D%200.1%20mm%2Fmm%20%3D%20%5Cfrac%7B0.1%7D%7B1000%7D%20%3D%200.1%20%2A10%5E%7B-3%7D%20m%2Fm)
The contact area is
Looking at the first diagram
At 600 MPa of stress
The strain is ![0.3mm/mm](https://tex.z-dn.net/?f=0.3mm%2Fmm)
At 450 MPa of stress
The strain is ![0.0015 mm/mm](https://tex.z-dn.net/?f=0.0015%20mm%2Fmm)
To find the stress at
we use the interpolation method
![\frac{\sigma_{\Delta l} - \sigma_{0.0015} }{ \sigma _ {0.3} - \sigma_{0.0015} } = \frac{e_{\Delta l } - e_{0.0015}}{e_{0.3} - e_{ 0.0015}}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csigma_%7B%5CDelta%20l%7D%20-%20%20%5Csigma_%7B0.0015%7D%20%7D%7B%20%5Csigma%20_%20%7B0.3%7D%20-%20%5Csigma_%7B0.0015%7D%20%7D%20%3D%20%5Cfrac%7Be_%7B%5CDelta%20l%20%7D%20%20-%20e_%7B0.0015%7D%7D%7Be_%7B0.3%7D%20-%20e_%7B%200.0015%7D%7D)
Substituting values
![\frac{\sigma _{\Delta l} - 450}{600 - 450} = \frac{0.1 -0.0015}{0.3 - 0.0015}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csigma%20_%7B%5CDelta%20l%7D%20-%20450%7D%7B600%20-%20450%7D%20%3D%20%5Cfrac%7B0.1%20-0.0015%7D%7B0.3%20-%200.0015%7D)
![\sigma _{\Delta l} -450 = 49.50](https://tex.z-dn.net/?f=%5Csigma%20_%7B%5CDelta%20l%7D%20-450%20%3D%2049.50)
![\sigma _{\Delta l} = 499.50 MPa](https://tex.z-dn.net/?f=%5Csigma%20_%7B%5CDelta%20l%7D%20%3D%20499.50%20MPa)
Generally the force on each head is mathematically represented as
![F = \sigma_{\Delta l} * A](https://tex.z-dn.net/?f=F%20%3D%20%5Csigma_%7B%5CDelta%20l%7D%20%2A%20A)
Substituting values
![F = 499.50*10^{6} * 2.8*10^{-6}](https://tex.z-dn.net/?f=F%20%3D%20499.50%2A10%5E%7B6%7D%20%2A%202.8%2A10%5E%7B-6%7D)
![=1398.6N](https://tex.z-dn.net/?f=%3D1398.6N)
Now the tension on the bolt shank is as a result of the force on the 6 head which is mathematically evaluated as
![T = 6 * F](https://tex.z-dn.net/?f=T%20%3D%206%20%2A%20F)
![= 6* 1398.6](https://tex.z-dn.net/?f=%3D%206%2A%201398.6)
![T =8391.6 N](https://tex.z-dn.net/?f=T%20%3D8391.6%20N)
Answer:
Water is not able to be used as a thermometer liquid because of its higher freezing point and lower boiling point than the other liquids in general. If water is used in a thermometer, it will start phase variation at 0∘C and 100∘C. This will not help in measuring temperature, beyond this range.
Explanation:
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Answer:
T= 4.24sec
Explanation:
We are going to use the formula below to calculate.
![T=2\pi \sqrt{\frac{L}{g} }](https://tex.z-dn.net/?f=T%3D2%5Cpi%20%5Csqrt%7B%5Cfrac%7BL%7D%7Bg%7D%20%7D)
Where T is period
L is length of rod
g is acceleration due to gravity =
From the problem, the rod is pivoted at 1/4L which means that three quarter of the rod was used for the oscillation. lets call this
![L_{O} = 3/4 * 5.95m](https://tex.z-dn.net/?f=L_%7BO%7D%20%3D%203%2F4%20%2A%205.95m)
= 4.4625m
thus
T= 4.24sec
"The" (and any subsequent words) was ignored because we limit queries to 32 words.