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den301095 [7]
3 years ago
8

F-40Nm=5kk = 0,2a=? ​

Physics
1 answer:
tester [92]3 years ago
3 0

Answer:

1......... .......... ......

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Which of the following statements is not one of Newton's laws of motion?
Alex17521 [72]

Answer:

The answer to your question: d.

Explanation:

a. The rate of change of momentum of an object is equal to the net force applied to the object.  

This is the second a law of motion, so this answer is incorrect.

b. In the absence of a net force acting on it, an object moves with constant velocity.

This is the first Newton law of motion, so this option is not correct.

c. For any force, there always is an equal and opposite reaction force.

This is the third law of motion, so this is not the right option.

d. What goes up must come down.

Newton said this sentence, but is not part of the law of motion.

5 0
3 years ago
A cart travels 4.00 meters east and then4.00 meters north. determine the magnitude ofthe cart’s resultant displacement.
gogolik [260]
^
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Square root of (4^2 + 4^2) = 4*squareRoot(2)
7 0
3 years ago
If we double the frequency of a system undergoing simple harmonic motion, which of the following statements about that system ar
AnnyKZ [126]

Answer:

a. The angular frequency is doubled.

e. The period is reduced to one-half of what it was.

Explanation:

Angular frequency is given as;

ω = 2πf

\frac{\omega _1}{f_1} = \frac{\omega _2}{f_2}

when the frequency is doubled

\frac{\omega _1}{f_1} = \frac{\omega _2}{(2f_1)} \\\\\omega _1 = \frac{\omega _2}{2}\\\\\omega _2 = 2\omega _1

Thus, the angular frequency will be doubled.

Amplitude in simple harmonic motion is the maximum displacement.

Frequency is related to period in simple harmonic motion as given in the equation below;

f = \frac{1}{T} \\\\f_1T_1= f_2T_2\\\\T_2 = \frac{f_1T_1}{f_2}

when the frequency is doubled;

T_2 = \frac{f_1T_1}{2f_1} \\\\T_2 = \frac{T_1}{2}

Thus, the period will be reduced to one-half of what it was.

5 0
3 years ago
An object is moring in a negative direction with a negative acceleration, for example an object dropped out a vindow. What does
Lina20 [59]

Answer:

Its slowing down

Explanation:

I just took the test for it

5 0
3 years ago
A certain instant camera determines the distance to the subject by sending out a sound wave and measuring the time needed for th
valentinak56 [21]
The total distance covered by the sound wave is twice the distance between the camera and the subject (because the wave has to reach the subject and then travel back to the camera), so 2L, where L=3.42 m. The speed of sound is v=343 m/s. It is a uniform linear motion, so we can use the basic relationship between space (S), time (t) and velocity (v) to find the time the wave needs to return to the camera:
t= \frac{S}{v}= \frac{2L}{v}= \frac{2\cdot 3.42 m}{343 m/s}=0.020 s
6 0
3 years ago
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