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Assoli18 [71]
3 years ago
6

I need help with this question

Mathematics
1 answer:
qwelly [4]3 years ago
4 0

Answer:

sin\theta = \frac{5}{14}\\\\\theta = sin^-1 \frac{5}{14}\\\\\theta = 20.9

Option B: 20.9°

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Which of the following constants can be added to x^2 + 2/3x to form a perfect square trinomial?
Angelina_Jolie [31]
Hello.

A trinomial is a perfect square if the square root of the first term times the square root of the third term times 2 equals the middle term.

\boxed{\mathsf{x^{2} + \dfrac{2}{3} x}}

a) Adding 1/9:

\cdot \: \mathsf{x^{2} + \dfrac{2}{3} x + \dfrac{1}{9}} \\ \\ \\ \mathsf{\sqrt{x^{2}} \times \sqrt{\dfrac{1}{9}} \times 2 =} \\ \\ \\ \mathsf{x \times \dfrac{1}{3} \times 2 =} \\ \\ \\ \mathsf{\dfrac{2}{3} x \rightarrow it \: is \: a \: perfect \: square \: trinomial}

b) Adding 4/9:

\cdot \: \mathsf{x^{2} + \dfrac{2}{3} x + \dfrac{4}{9}} \\ \\ \\ \mathsf{\sqrt{x^{2}} \times \sqrt{\dfrac{4}{9}} \times 2 =} \\ \\ \\ \mathsf{x \times \dfrac{2}{3} \times 2 =} \\ \\ \\ \mathsf{\dfrac{4}{3} x \rightarrow it \: is \: not \: a \: perfect \: square \: trinomial}

c) Adding 4 and 1/9:

\cdot \: \mathsf{x^{2} + \dfrac{2}{3} x + \dfrac{1}{9} + 4 = x^{2} + \dfrac{2}{3} x + \dfrac{37}{9}} \\ \\ \\ \mathsf{\sqrt{x^{2}} \times \sqrt{\dfrac{37}{9}} \times 2 =} \\ \\ \\ \mathsf{x \times \dfrac{\sqrt{37}}{3} \times 2 =} \\ \\ \\ \mathsf{\dfrac{2\sqrt{37}}{3} x \rightarrow it \: is \: not \: a \: perfect \: square \: trinomial}

Hope I helped.
3 0
3 years ago
It’s geometry I need help
Gnom [1K]
Answer: Parallel

Y=x will be on the point of the graph
Y= x+2 will be two units up but still positive so they will never interest
6 0
3 years ago
Read 2 more answers
Helen's house is located on a rectangular lot that is1 1-8 miles by 9/10 mile.Estimate the distance around the lot
klemol [59]

Answer: The distance around the lot is given by

4\frac{1}{20}\ miles

Step-by-step explanation:

Since we have given that

Length of rectangular lot is given by

1\frac{1}{8}\\\\=\frac{9}{8}\ miles

Width of rectangular lot is given by

\frac{9}{10}\ mile

We need to find the distance around the lot.

As we know the formula for "Perimeter of rectangle":

Perimeter=2(Length+Width)\\\\Perimeter=2(\frac{9}{8}+\frac{9}{10})\\\\Perimeter=2(\frac{45+36}{40})\\\\Perimeter=2\times \frac{81}{40}\\\\Perimeter=\frac{81}{20}\\\\Perimeter=4\frac{1}{20}\ miles

Hence, the distance around the lot is given by

4\frac{1}{20}\ miles


3 0
3 years ago
Read 2 more answers
10m^2-20m+48=0 solve by completing the square please show your work please.
sergejj [24]

Answer:

m = {-6, -4}

Step-by-step explanation:

<u><em>Subproblem 1:</em></u>

Set the factor '(6 + m)' equal to zero and attempt to solve:

Simplifying

6 + m = 0

Solving

6 + m = 0

Move all terms containing m to the left, all other terms to the right.

Add '-6' to each side of the equation.

6 + -6 + m = 0 + -6

Combine like terms: 6 + -6 = 0

0 + m = 0 + -6

m = 0 + -6

Combine like terms: 0 + -6 = -6

m = -6

Simplifying

m = -6

<u><em>Subproblem 2:</em></u>

Set the factor '(4 + m)' equal to zero and attempt to solve:

Simplifying

4 + m = 0

Solving

4 + m = 0

Move all terms containing m to the left, all other terms to the right.

Add '-4' to each side of the equation.

4 + -4 + m = 0 + -4

Combine like terms: 4 + -4 = 0

0 + m = 0 + -4

m = 0 + -4

Combine like terms: 0 + -4 = -4

m = -4

Simplifying

m = -4

6 0
3 years ago
Point C has a _____ abscissa and a _____ ordinate.
vampirchik [111]
Based on the picture above,

i think point C has  a Positive abscissa and a Negative ordinate

Hope this helps
7 0
3 years ago
Read 2 more answers
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