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RUDIKE [14]
2 years ago
7

In what specific situations would you use a light microscope? an electronmicroscope?​

Chemistry
1 answer:
galina1969 [7]2 years ago
7 0

ANSWER

A standard light microscope is used to view living organisms with little contrast to distinguish them from the background, which would be harder to see with the electron microscope.

Electron microscopes can be used to examine not just whole cells, but also the subcellular structures and compartments within them.

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hydrogen gas and oxygen gas react to form liquid hydrogen peroxide. which starement is true about the reaction?
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The two elements mixed together to form a chemical bond and reacted as a chemical change
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Draw an ether that contains exactly five carbon atoms and only single bonds
Eddi Din [679]

<em>Answer:</em>

  •                                       H3CH2COCH2CH2CH3

<em>Ether:</em>

Ether are organic compounds that contain ether functional group , in which oxygen atom is connected with two alkyl or aryl group.

They have general formula as follow

  • R---O---R   or R'---O----R or R'---O---R'

            while  R = Alkyl

                       R' = Aryl

8 0
2 years ago
A sample of aluminum, which has a specific heat capacity of , is put into a calorimeter (see sketch at right) that contains of w
Oksanka [162]

Complete Question

A sample of aluminum, which has a specific heat capacity of 0.897 JB loc ! is put into a calorimeter (see sketch at right) that contains 200.0 g of water. The aluminum sample starts off at 85.6 °C and the temperature of the water starts off at 16.0 °C. When the temperature of the water stops changing it's 20.1 °C. The pressure remains constant at 1 atm. Calculate the mass of the aluminum sample.

Answer:

M=58g

Explanation:

From the question we are told that:

Heat Capacity H=0.897

Mass of water M=200g

Initial Temperature of Aluminium T_a=85.6

Initial Temperature of Water T_{w1}=16.0

Final Temperature of Water  T_{w2}=16.0

Generally

Heat loss=Heat Gain

Therefore

M*0.897*(85.6-20.1) =200*4.184*(20.1-16)

M=58g

5 0
2 years ago
If the temperature of a gas is increased from 20°C to 35°C, what is the new pressure if the original pressure was 1.2 atm? Assum
Marta_Voda [28]

Answer:

B.) 1.3 atm

Explanation:

To find the new pressure, you need to use Gay-Lussac's Law:

P₁ / T₁ = P₂ / T₂

In this equation, "P₁" and "T₁" represent the initial pressure and temperature. "P₂" and "T₂" represent the final pressure and temperature. After converting the temperatures from Celsius to Kelvin, you can plug the given values into the equation and simplify to find P₂.

P₁ = 1.2 atm                                    P₂ = ? atm

T₁ = 20 °C + 273 = 293 K              T₂ = 35 °C + 273 = 308 K

P₁ / T₁ = P₂ / T₂                                             <----- Gay-Lussac's Law

(1.2 atm) / (293 K) = P₂ / (308 K)                  <----- Insert values

0.0041 = P₂ / (308 K)                                   <----- Simplify left side

1.3 = P₂                                                         <----- Multiply both sides by 308

3 0
11 months ago
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