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RUDIKE [14]
2 years ago
7

In what specific situations would you use a light microscope? an electronmicroscope?​

Chemistry
1 answer:
galina1969 [7]2 years ago
7 0

ANSWER

A standard light microscope is used to view living organisms with little contrast to distinguish them from the background, which would be harder to see with the electron microscope.

Electron microscopes can be used to examine not just whole cells, but also the subcellular structures and compartments within them.

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If we wish to prepare 250. mL of 0.200 M BaCl2 solution, how much solid BaCl2 is needed?
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10.4g

Explanation are in the Picture

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ethylene and steam at 320 celsius and 1 atm are fed to a reaction process as an equimolar mixture. the process produces ethanol
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Answer:

Total amount of heat transfer, H_total = 115653.232 J/mol

Explanation:

Full explanation and step by step instructions is attached

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3 years ago
Help plz help
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4 0
2 years ago
Caffeine, a stimulant found in coffee and soda, hasthe mass percent composition: C. 49.48%, H, 5.19%. N. 28.85% 0. 16.48% The mo
borishaifa [10]

We have the next % composition:

C. 49.48%

H, 5.19%.

N. 28.85%

0. 16.48%

We assume 100 g of sample

1) As we have 100 g of sample of Caffeine, we calculate the mass of each element involved here.

C. 49.48 g

H, 5.19 g

N. 28.85 g

0. 16.48 g

2) We calculate the number of moles of each element (we need the mass per mole of each element)

For C) 12.01 g/mol

49.48 g x (1 mol/12.01 g) = 4.120 moles

For H) 1.007 g/mol

5.19 g x (1 mol/1.007 g) = 5.154 moles

For O) 15.99 g/mol

16.48 g x (1 mol/15.99 g) = 1.030 moles

For N) 14.00 g/mol

28.85 g x (1 mol/14.00 g) = 2.060 moles

3) We choose the smallest number from 2) and divide the rest of them by it.

For C) 4.120 moles/1.030 moles= 4

For H) 5.154 moles/1.030 moles= 5

For O) 1.030 moles/1.030 moles= 1

For N) 2.060 moles/1.030 moles= 2

4) The numbers in 3) represents the subindex from the empirical formula of caffeine:

C_4H_5O_1N_2

5) We calculate the molar mass of our empirical formula, 97.06 g/mol.

We already have the molar mass of the molecular formula, so we proceed like this:

n= the molar mass of the molecular formula/the molar mass of the empirical formula

n = 194.19 g/mol/97.06 g/mol = 2 approx.

We use "n" and we multiply our empirical formula by n = 2:

Therefore, our molecular formula:

C_8H_{10}O_2N_4

8 0
1 year ago
How can separate the mixture of sugar and salt
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Mixing them in different bowls
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2 years ago
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