Answer:
Zn3P2O8
Explanation:
In this particular question, it is necessary to convert the respective masses to percentages. We convert to percentages by placing each mass over the total mass and multiplying by 100%. Since the total is 50mg, conversion to percentage can be done by multiplying the masses by 2 as 100/50 is 2
For Oxygen = 16.58 * 2 = 33.16%
For phosphorus = 8.02 * 2 = 16.04%
For zinc = 25.40 * 2 = 50.80%
We then proceed to divide these percentages by their respective atomic masses. The atomic mass of oxygen, phosphorus and zinc are 16, 31 and 65 respectively.
O = 33.16/16 = 2.0725
P = 16.04/31 = 0.5174
Zn = 50.80/65 = 0.7815
Now, we divide by the smallest value which is that of the phosphorus
O = 2.0725/0.5174 = 4
P = 0.5174/0.5174 = 1
Zn= 0.7815/0.5174 = 1.5
Now, we need to multiply through by 2. This yields: O = 8, P = 2 and Zn = 3
The empirical formula is thus: Zn3P2O8
Answer:
When we look at an arbitrary point in the sky, away from the sun, we see only the light that was redirected by the atmosphere into our line of sight. Because that occurs much more often for blue light than for red, the sky appears blue. Violet light is actually scattered even a bit more strongly than blue.
Explanation:
<u>Answer:</u> The sample of Carbon-14 isotope will take 2377.9 years to decay it to 25 %
<u>Explanation:</u>
The equation used to calculate rate constant from given half life for first order kinetics:
where,
= half life of the reaction = 5730 years
Putting values in above equation, we get:
Rate law expression for first order kinetics is given by the equation:
![k=\frac{2.303}{t}\log\frac{[A_o]}{[A]}](https://tex.z-dn.net/?f=k%3D%5Cfrac%7B2.303%7D%7Bt%7D%5Clog%5Cfrac%7B%5BA_o%5D%7D%7B%5BA%5D%7D)
where,
k = rate constant = 
t = time taken for decay process = ? yr
![[A_o]](https://tex.z-dn.net/?f=%5BA_o%5D)
= initial amount of the sample = 100 grams
[A] = amount left after decay process = (100 - 25) = 75 grams
Putting values in above equation, we get:
Hence, the sample of Carbon-14 isotope will take 2377.9 years to decay it to 25 %
