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sleet_krkn [62]
3 years ago
15

How much does the force increase if each mass is doubled?

Physics
1 answer:
Schach [20]3 years ago
8 0

Answer:

The force will also double

Explanation:

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If the diameter of each of a car's wheels is 0.4 meters, approximately, what was the average speed of the car for its three-hour
Reptile [31]

Answer:

42 km/h was the average speed of the car for its three-hour trip.

Explanation:

Diameter of the car wheel = d = 0.4 m

Radius of the car wheel = r = 0.5 d = 0.5 × 0.4 m =0.2 m

Distance covered in 1 complete revolution = 2\pi r

Distance covered in 100,000 complete revolution,D = 2\pi r\times 100,000

D=2\times 3.14\times 0.2 m\times 100,000=125,663.71 m

1 m = 0.001 km

125,663.71 m = 125,663.71 × 0.001 km = 125.66371 km

Time taken to complete 100,000 revolution by a wheel = t = 3 hours

Speed of car : S

S=\frac{125.66371 km}{3hours}=41.89 km/h\approx 42 km/h

42 km/h was the average speed of the car for its three-hour trip.

8 0
3 years ago
Read 2 more answers
Which of these forces are acting within a nucleus? Check all that apply.
zavuch27 [327]

Answer:

Excuse me what?

Explanation:

5 0
3 years ago
Cause and Effect: What would happen to a space vehicle in orbit around Earth if it sped up?
gulaghasi [49]

Answer:

G M m / R^2 = m v^2 / R     gravitational force = centripetal force

G M = v^2 R   =    constant

As v increases R will must decrease

Take the moon as an example

S = 2 pi R   where R is about 240,000 miles for one orbit

S / 1 day = 54,000 miles/day  for a 28 day circuit

S / 1 hr = 54000 / 24 = 2200 mph  which is much less than a satellite in orbit

4 0
3 years ago
A 1.4-kg block slides freely across a rough surface such that the block slows down with an acceleration of â1.25 m/s2. what is t
Marianna [84]

Mass of the block = 1.4 kg

Weight of the block = mg = 1.4 × 9.8 = 13.72 N

Normal force from the surface (N) = 13.72 N

Acceleration = 1.25 m/s^2

Let the coefficient of kinetic friction be μ

Friction force = μN

F(net) = ma

μmg = ma

μg = a

μ = \frac{a}{g}

μ = \frac{1.25}{9.8}

μ = 0.1275

Hence, the coefficient of kinetic friction is: μ = 0.1275

6 0
3 years ago
A 45.0 kg ice skater needs a 25 N horizontal force to get moving on a smooth ice surface. What is the coefficient of friction be
SVEN [57.7K]
The horizontal force : f = k*N
k- coefficient of friction
k = f /N
N = m * g = 45 kg * 9.81 m/s² = 441.45 N
k = 25 N : 441.45 N = 0.057
Answer C) 0.057
7 0
3 years ago
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