Answer:
the magnitude of the total electric field is 25 V/m
Explanation:
Given data
point above = 0.5 m
charges = 18 V/m
to find out
the magnitude of the total electric field
solution
the magnitude of the total electric field is 25 V/m because number is less than the twice magnitude of field by every charge and the horizontal component in electric field by every charge cancel out and vertical component in field added together
I would use meter and second.
Hope this helps.
Answer:
Explanation:
An object falling loses gravitational potential energy and gains kinetic energy. The gravity potential is the gravitational potential energy per unit mass. This energy comes from the gravitational potential energy released when the water falls. ... At 0, all the energy is in gravitational potential energy.
Answer:
b. The internal resistance must be much smaller than the other resistances in the circuit.
Explanation:
Ammeter is used to measure the current flowing through a circuit. It is connected in series configuration with the load. In such a scenario the resistance of the ammeter should be negligible so as to make sure that the voltage drop across the resistance of ammeter is zero and it shows the correct reading of the current in the circuit.
This depends on the direction of the velocity vector to the magnetic field vector. The force is F=q(VxB) ("x" is the cross product.) The max force is when V and B are perpendicular. Then F=qVB = (1.602e-19)(2000)(300) = 9.612e-14 N
