I would say the energy has to be decreased by 87 kj because the bonding is held together by 87 kj so removing that should prevent the bonding from taking place or reverse it I believe. In other words, a certain amount of energy is required to hold the bond together and in the absence of that energy, the bonding will not take place.
<span>The electron transport process makes water and ATP and is sometimes called Oxidative phosphorylation because it requires oxygen.</span>
Answer:
molecular weight (Mb) = 0.42 g/mol
Explanation:
mass sample (solute) (wb) = 58.125 g
mass sln = 750.0 g = mass solute + mass solvent
∴ solute (b) unknown nonelectrolyte compound
∴ solvent (a): water
⇒ mb = mol solute/Kg solvent (nb/wa)
boiling point:
- ΔT = K*mb = 100.220°C ≅ 373.22 K
∴ K water = 1.86 K.Kg/mol
⇒ Mb = ? (molecular weight) (wb/nb)
⇒ mb = ΔT / K
⇒ mb = (373.22 K) / (1.86 K.Kg/mol)
⇒ mb = 200.656 mol/Kg
∴ mass solvent = 750.0 g - 58.125 g = 691.875 g = 0.692 Kg
moles solute:
⇒ nb = (200.656 mol/Kg)*(0.692 Kg) = 138.83 mol solute
molecular weight:
⇒ Mb = (58.125 g)/(138.83 mol) = 0.42 g/mol
Answer:
338.00 mL
Explanation:
The lead ions come from the salt Pb(NO₃)₂ and the iodide from the acid HI, so the balanced reaction is:
Pb(NO₃)₂(aq) + 2HI(aq) → PbI₂(s) + 2HNO₃(aq)
So, the stoichiometry is 1 mol of Pb(NO₃)₂ to 2 moles of HI, then:
1 mol of Pb(NO₃)------------------------------------ 2 moles of HI
0.600 mol of Pb(NO₃)₂--------------------------- x
By a simple direct three rule:
x = 1.200 mol of HI
The acid has concentration equal to 3.550 mol/L, the volume (V) is the number of moles divided by the molar concentration:
V = 1.200/3.550 = 0.338 L
V = 338.00 mL
