Answer:
Under high temperatures and low pressure, gases behave the most ideal.
Explanation:
Low pressure reduces the effect of the finite size of real particles by increasing the volume around each particle, and a high temperature gives enough kinetic energy to the particles to better overcome the attractions that exist between real particles. (Prevents sticking.)
In summary, real gases behave more like ideal gases when they are far away from a phase boundary, (condensation or freezing).
Answer:
68.3 kilo Pascal is the pressure in the container.
Explanation:
To calculate the new pressure , we use the equation given by Boyle's law. This law states that pressure is inversely proportional to the volume of the gas at constant temperature.
The equation given by this law is:
where,
are initial pressure and volume.
are final pressure and volume.
We are given:
Putting values in above equation, we get:
68.3 kilo Pascal is the pressure in the container.
Answer:
Explanation:
3: Given data:
Number of moles of strontium nitrate = 3.00×10⁻³ mol
Number of atoms = ?
Solution:
There are 9 moles of atoms in 1 mole of Sr(NO₃)₂.
In 3.00×10⁻³ moles,
9 mol × 3.00×10⁻³
27.00×10⁻³ mol
Number of atoms in 3.00×10⁻³ mol of Sr(NO₃)₂:
27.00×10⁻³ mol × 6.022×10²³ atoms / 1mol
162.59×10²⁰ atoms
4)Given data:
Mass of calcium hydroxide = 4500 Kg (4500/1000 = 4.5 g)
Number of moles = ?
Solution:
Number of moles = mass in g/molar mass
by putting values,
Number of moles = 4.5 g/ 74.1 g/mol
Number of moles = 0.06 mol
5) Given data:
Number of atoms of silver nitrate = 1.06×10²³
Number of moles = ?
Solution:
1 mole of any substance contain 6.022×10²³ atoms .
1.06×10²³ atoms × 1 mol / 6.022×10²³ atoms
0.176 moles of silver nitrate
Moles of Lithium phosphate : 0.495
<h3>Further explanation</h3>
Given
6 Li + Zn₃(PO₄)₂ ------- > 2 Li₃PO₄ + 3 Zn
Required
Moles of Lithium phosphate
Solution
moles of Zinc(Ar=65,38 g/mol) :
= mass : Ar
= 48.6 : 65.38
= 0.743
From equation, mol ratio of Zn : Li₃PO₄ = 3 : 2, so mol Li₃PO₄ :
= 2/3 x mol Zn
= 2/3 x 0.743
= 0.495
Answer : The value of 'R' is 
Solution : Given,
At STP conditions,
Pressure = 1 atm
Temperature = 273 K
Number of moles = 1 mole
Volume = 22.4 L
Formula used : 
where,
R = Gas constant
P = pressure of gas
T = temperature of gas
V = volume of gas
n = number of moles of gas
Now put all the given values in this formula, we get the values of 'R'.
Therefore, the value of 'R' is .
