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3 years ago

What is the product of the polynomials x2-5 and x3 - 6?

Mathematics

1 answer:

-BARSIC- [3]3 years ago

7 0

Step-by-step explanation:

Please refer to the attachment

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Find the zero of the function /(x) = 5x-3.

Bad White [126]

Answer:

3/5

Step-by-step explanation:

Set it equal to 0

5x-3=0

Then solve for x

5x=3

x=3/5

Check

5(3/5) - 3

3-3

4 0

3 years ago

What is 38475 x 304944 ? My teacher won't let me use a calculator!

bearhunter [10]

Answer:

1,059,680,400

Step-by-step explanation:

7 0

2 years ago

Solve by factorization 2x^2 + 3x -20 = 0

saul85 [17]

Answer:

x=2.5 or x=-4

Step-by-step explanation:

factorisation= factors:1, 2, 4, 5, 10, 20 (only the positive factors)

We will use the factors 4 and 5.

=(2x-5)(x+4)=0

2x-5=0 || x+4=0

2x=+5 || x=-4

x=2.5 or x=-4

4 0

3 years ago

Read 2 more answers

16^3x+8^x+6 Could you please give me the steps as well for this problem?

BARSIC [14]

Answer:

x = 2

Step-by-step explanation:

$16^{3x} = 8^{x+6} \\2^{4(3x)} = 2^{3(x+6)} -->$ (16 = $2^{4}$ and 8 = $2^{3}$ )

$2^{12x} = 2^{3x+18}$

Since the base number is 2, the exponents must equal each other.

So:

12x = 3x+18

9x = 18

x = 2

8 0

3 years ago

A village fete has a children’s running race each year, run in heats of up to ten children. For each heat the first three contes

bekas [8.4K]

Answer: 1) 1/3,654 2) 3/406 3) 72,684,900,288,000 4) 120

Step-by-step explanation:

1) First and Second and Third

$\dfrac{3\ total\ prizes}{29\ total\ people}\times \dfrac{2\ remaining\ prizes}{28\ remaining\ people}\times \dfrac{1\ remaining\ prize}{27\ remaining\ people}=\dfrac{6}{21,924}\\\\\\.\qquad \qquad \qquad \qquad \qquad \qquad \qquad \qquad \qquad \qquad \qquad \qquad \qquad \quad =\large\boxed{\dfrac{1}{3,654}}$

2) First and Second

$\dfrac{3\ total\ prizes}{29\ total\ people}\times \dfrac{2\ remaining\ prizes}{28\ remaining\ people}=\dfrac{6}{812}=\large\boxed{\dfrac{13}{406}}$

$3)\quad \dfrac{29!}{(29-10)!}=\large\boxed{72,684,900,288,000}$

$4)\quad _{10}C_3=\dfrac{10!}{3!(10-3)!}=\large\boxed{120}$

8 0

3 years ago