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3 years ago

What is the product of the polynomials x2-5 and x3 - 6?

Mathematics

1 answer:

-BARSIC- [3]3 years ago

7 0

Step-by-step explanation:

Please refer to the attachment

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Solve the equations to find the number and type of solutions

luda_lava [24]

Answer:

This has one real solution, x=4

Step-by-step explanation:

8 - 4x = 0

Add 4x to each side

8 - 4x+4x = 0+4x

8 =4x

Divide each side by 4

8/4 = 4x/4

2 =x

This has one real solution, x=4

6 0

3 years ago

Read 2 more answers

What value makes x - 7 = -6 equation true?

Bumek [7]

Answer:

x=1

Step-by-step explanation:

In order to solve this equation, we must add 7 to each side. This gives us x=1

$x-7=-6\\\\x=1$

4 0

3 years ago

.A bacteria culture grows at a rate of 20%

Zolol [24]

The number of the specimens would be in the culture after 5 minutes will be 7,962.62.

<h3>What is an exponent?</h3>

Consider the function:

y = a (1 + r) ˣ

Where x is the number of times this growth occurs, a = initial amount, and r = fraction by which this growth occurs.

A bacteria culture grows at a rate of 20% per minute.

If the culture initially has 3,200 bacteria specimens.

Then the equation will be

y = 3200 (1 + 0.2) ˣ

y = 3200 (1.20) ˣ

Then the number of the specimens would be in the culture after 5 minutes will be

y = 3200 (1.20)⁵

y = 7962.62

More about the exponent link is given below.

brainly.com/question/5497425

#SPJ1

5 0

2 years ago

Pls look at picture and answer

Kay [80]

Answer:

i cant see the picture

Step-by-step explanation:

it looks pretty blurry

3 0

3 years ago

When the effective interest rate is 9% per annum, what is the present value of a series of 50 annual payments that start at $100

ser-zykov [4K]

Answer:

$1,109.62

Step-by-step explanation:

Let's first compute the future value FV.

In order to see the rule of formation, let's see the value (in $) for the first few years

End of year 0

1,000

End of year 1(capital + interest + new deposit)

1,000*(1.09)+10

End of year 2 (capital + interest + new deposit)

(1,000*(1.09)+10)*1.09 +10 =

$\bf 1,000*(1.09)^2+10(1+1.09)$

End of year 3 (capital + interest + new deposit)

$\bf (1,000*(1.09)^2+10(1+1.09))(1.09)+10=\\1,000*(1.09)^3+10(1+1.09+1.09^2)$

and we can see that at the end of year 50, the future value is

$\bf FV=1,000*(1.09)^{50}+10(1+1.09+(1.09)^2+...+(1.09)^{49}$

The sum

$\bf 1+1.09+(1.09)^2+...+(1.09)^{49}$

is the sum of a geometric sequence with common ratio 1.09 and is equal to

$\bf \frac{(1.09)^{50}-1}{1.09-1}=815.08356$

and the future value is then

$\bf FV=1,000*(1.09)^{50}+10*815.08356=82,508.35564$

The present value PV is

$\bf PV=\frac{FV}{(1.09)^{50}}=\frac{82508.35564}{74.35572}=1,109.616829\approx \$1,109.62$

rounded to the nearest hundredth.

5 0

3 years ago