Answer:
Explanation:
Let us study the downward movement of cylinder which accelerates as well as rotates .
A)
If v be the linear downward velocity of cm of cylinder and ω be angular velocity of cylinder
v = ωr , when there is no slippage of string around cylinder.
B &C )
Total kinetic energy = Rotational + linear
= 1/2 Iω² + 1/2 m v²
1/2 x1/2 mr²ω² +1/2 m v²
= 1/4 mv² +1/2 m v²
= 3/4 m v²
For downward acceleration ,
mg - T = ma where T is tension in string.
Rotational movement
Torque = T x r
Tr = I α , I is moment of inertia and α is angular acceleration .
= I a/r
T = I a / r² , Putting this value of T in earlier equation
mg - I a / r² = ma
a (I / r² +m )= mg
a = mg / (I / r² +m )
For cylinders
I = .5 mr²
a = g / (.5 +1)
= g / 1.5
Answer:
Over tens of millions of years, the giant supercontinent Pangaea began to slowly drift apart, forming the continents as they are known today.
Explanation:
Answer:
a)40100m/s
b)-4.348x10^- m/s^2
Explanation:
to calculate the change in the planet's velocity we have to rest the speeds
ΔV=-22.8-17.3=-40.1km/s=40100m/s
A body that moves with constant acceleration means that it moves in "a uniformly accelerated movement", which means that if the velocity is plotted with respect to time we will find a line and its slope will be the value of the acceleration, it determines how much it changes the speed with respect to time.
When performing a mathematical demonstration, it is found that the equations that define this movement are as follows.
Vf=Vo+a.t (1)\\\\
{Vf^{2}-Vo^2}/{2.a} =X(2)\\\\
X=Xo+ VoT+0.5at^{2} (3)\\
Where
Vf = final speed
Vo = Initial speed
T = time
A = acceleration
X = displacement
In conclusion to solve any problem related to a body that moves with constant acceleration we use the 3 above equations and use algebra to solve
for this problem we have to convert the time interval ins seconds, we know that a year has 53926560s
t=1.71years=53926560*1.71=92214417.6
then we can use the ecuation number 1 to calculate the aceleration
Vf=-22.8km/s
Vo=17.3km/s
Vf=Vo+at
a=(vf-vo)/t
a=(-22.8-17.3)/92214417.6
a=-4.348x10^-7 km/s^2=-4.348x10^- m/s^2
Explanation:
work done by friction = 1/2 x 42 x ( 3.33^2 - 11.5^2)
= 21 ( 11.08 - 132.25)
= 21 ( - 121.17 )
= - 2544.57 J