Ask question

Ask question

All categories

4 years ago

8

Get the lead out! That is really graphite in your pencil, not lead. Graphite is a form of carbon. Use the physical properties of

graphite to classify it using the choices below. A) metal B) nonmetal C) metalloid D) rare Earth element

2 answers:

Svetllana [295]4 years ago

5 0

NON-METAL!!!!!!!!!!!!!!!!!!!!!!!!!!!

Alja [10]4 years ago

4 0

The answer to this question is B. Nonmetal

You might be interested in

You are an astronaut on a spacewalk to fix your spacecraft with a hammer. Your lifeline (tether) breaks and your jetpack on your

tamaranim1 [39]

Explanation:

Here we will apply the law of conservation of momentum which is one of the powerful laws of physics. As this law states that the "if no external forces are acting on the system then the net momentum of the system before and after must remain conserved. As the astronaut has a hammer, if he throws it in the direction opposite of his space craft, he will automatically move towards the space craft to conserve the momentum. That's how he can reach the space craft easily by throwing away the hammer.

8 0

3 years ago

Read 2 more answers

With a frequency of 500 hz, what is the period of a wave

Pavlova-9 [17]

<span>500 hz means 500 times in a second therefore its 2.</span>

5 0

3 years ago

1) If you release a rubber band that had 10 units of elastic energy, 12 units of movement energy cannot be produced. Why not?

Mila [183]

Answer:

press dat crown for meh

Explanation:

4 0

3 years ago

Read 2 more answers

When a carpenter shuts off his circular saw, the 10.0 inch diameter blade slows from 4250 rpm to 0.00 in 4.00 s. (a) What is the

MaRussiya [10]

Answer:

(a) $\alpha=-111.26rad/s$

(b) $s=4450.6in$

(c) $8.66in$

Explanation:

First change the units of the velocity, using these equivalents $1rev=2\pi rad$ and $1 min =60s$

$4250rpm(\frac{2\pi rad}{1rev})(\frac{1 min}{60 s} )=445.06rad/s$

The angular acceleration $\alpha$ the time rate of change of the angular speed $\omega$ according to:

$\alpha=\frac{\Delta \omega}{\Delta t}$

$\Delta \omega=\omega_i-\omega_f$

Where $\omega_i$ is the original velocity, in the case the velocity before starting the deceleration, and $\omega_f$ is the final velocity, equal to zero because it has stopped.

$\alpha=\frac{\Delta \omega}{\Delta t} =\frac{\omega_i-\omega_f}{4}\frac{0-445.06}{4} =\frac{-445.06}{4} =-111.26rad/s$

b) To find the distance traveled in radians use the formula:

$\theta = \omega_i t + \frac{1}{2} \alpha t^2$

$\theta = 445.06 (4) + \frac{1}{2}(-111.26) (4)^2=1780.24-890.12=890.12rad$

To change this result to inches, solve the angular displacement $\theta$ for the distance traveled $s$ ( $r$ is the radius).

$\theta=\frac{s}{r} \\s=\theta r$

$s=890.12(5)=4450.6in$

c) The displacement is the difference between the original position and the final. But in every complete rotation of the rim, the point returns to its original position. so is needed to know how many rotations did the point in the 890.16 rad of distant traveled:

$\frac{890.12}{2\pi}=141.6667$

The real difference is in the 0.6667 (or 2/3) of the rotation. To find the distance between these positions imagine a triangle formed with the center of the blade (point C), the initial position (point A) and the final position (point B). The angle $\gamma=\frac{2\pi}{3}=\frac{360^o}{3}=120$ is between the two sides known. Using the theorem of the cosine we can find the missing side of the the triangle(which is also the net displacement):

$c^2=a^2+b^2-2abcos(\gamma)$

$c^2=5^2+5^2-2(5)(5)cos(\frac{2\pi}{3} )\\c^2=25+25+25\\c^2=75\\c=5\sqrt{3}=8.66in$

4 0

4 years ago

How does a boulder change

Minchanka [31]

a boulder can change due to erosion and weathering. it can change shape and sometimes color, possibly.

3 0

3 years ago